mou*_*que 5 jquery grid-layout
嘿,这是我的另一个关于jquery的问题和gridlayout我用开关做了一个php模板,我插入的代码就是这个
<div id="wrapper">
<div id="grid">
<div class="box"><img src="img/an_005_BUR_thebeat.jpg" width="310px" height="438px" />3 index</div>
<div class="box"><img src="img/an_014_GUE_homme_a.jpg" width="310px" height="404px" />4 Culture</div>
<div class="box"><img src="img/an_044_BVL_springmotiv.jpg" width="310px" height="310px" />5 Pharma</div>
<div class="box"><img src="img/an_039_AN_diskette.jpg" width="310px" height="465px" />6 Pharma IT</div>
<div class="box"><img width="310px" height="100px" />7 Culture</div>
<div class="box"><img width="310px" height="120px" />8 Cosmetics</div>
<div class="box"><img width="310px" height="400px" />9 IT</div>
<div class="box"><img width="310px" height="400px" />10 Culture</div>
<div class="box"><img width="310px" height="400px" />11 IT</div>
<div class="box"><img width="310px" height="400px" />12 Culture</div>
</div>
</div>
<script type="text/javascript">
$(document).ready(function(){
$('#grid').gridLayout('.box', {col_width: 340, min_cols: 2});
// options - (values above are the defaults)
// col_width: the width of each grid block
// min_cols: the minimum number of cols on the page (reducing browser width below this will not decrease number of columns). Set to your largest block (3 = block spans 3 columns)
// gridLayout.placeAtEnd() - for placing a block at bottom right of grid
var final_block = $('');
$('#grid').gridLayout.placeAtEnd( final_block );
// gridchange event fires when window resize forces a grid refresh
$('#grid').bind( "gridchange", function(e){
console.log('gridchange event fired');
// reposition the final block
$('#grid').gridLayout.placeAtEnd( final_block );
});
// this forces a redraw of grid
$('body').gridLayout.refresh();
// returns heights of each column
console.log( 'gridLayout.info():', $('#grid').gridLayout.info() );
});
</script>
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jquery脚本和插件加载到标头中.当我试图运行这个.萤火虫告诉我:
"节点无法插入层次结构中的指定点"代码:"3"
有谁知道如何解决这个问题?
这是我加载的一个例子:http://18735.webhosting7.1blu.de/neu/index.php?item = lifestyle
我很确定您的错误与以下内容有关.什么是$('')!
var final_block = $('');
$('#grid').gridLayout.placeAtEnd( final_block );
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如果我说,它的工作原理
var final_block = $('<div />');
$('#grid').gridLayout.placeAtEnd( final_block );
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