使用安全登录抓取网站内容

Question

我试图抓住一个网站的内容登录安全但无法做到该网站的登录有三个选项用户名,密码,密码这里是我正在使用的代码

<?php

// HTTP authentication

$url = "http://aftabcurrency.com/login_script.php";

$ch = curl_init();    

curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 

curl_setopt($ch, CURLOPT_URL, $url); 
$cookie = 'cookies.txt';
$timeout = 30;
curl_setopt($curl, CURLOPT_TIMEOUT,         10); 
curl_setopt($curl, CURLOPT_CONNECTTIMEOUT,  $timeout );
curl_setopt($curl, CURLOPT_COOKIEJAR,       $cookie);
curl_setopt($curl, CURLOPT_COOKIEFILE,      $cookie);

curl_setopt ($ch, CURLOPT_POST, 1); 
curl_setopt ($ch,CURLOPT_POSTFIELDS,"user_name=user&user_password=pass&passcode=code");             

$result = curl_exec($ch); 

curl_close($ch); 

echo $result;

?>

Answer 1

你需要做一个POST以http://aftabcurrency.com/login_script.php 您的卷曲的需求也接受cookies.
在验证之后,脚本将重定向您,因此您还需要添加CURLOPT_FOLLOWACTION.

这是您脚本的编辑版本,我无法在http://aftabcurrency.com/上测试它希望它有效:

$url = "http://aftabcurrency.com/login_script.php";

$ch = curl_init();    
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 

curl_setopt($ch, CURLOPT_URL, $url); 
$cookie = 'cookies.txt';
$timeout = 30;

curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_TIMEOUT,         10); 
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT,  $timeout );
curl_setopt($ch, CURLOPT_COOKIEJAR,       $cookie);
curl_setopt($ch, CURLOPT_COOKIEFILE,      $cookie);

curl_setopt ($ch, CURLOPT_POST, 1); 
curl_setopt ($ch,CURLOPT_POSTFIELDS,"user_name=user&user_password=pass&passcode=code");     

$result = curl_exec($ch);

/* //OPTIONAL - Redirect to another page after login
$url = "http://aftabcurrency.com/some_other_page";
curl_setopt ($ch, CURLOPT_POST, 0); 
curl_setopt($ch, CURLOPT_URL, $url);
$result = curl_exec($ch);
 */ //end OPTIONAL 

curl_close($ch); 
echo $result;