Google Apps脚本关闭()

Question

是否可以关闭在Apps脚本中打开的UI窗口？

我认为答案是不对的:http://code.google.com/p/google-apps-script-issues/issues/detail？id = 474&can = 1&q =.close%28%29&cospec = Stors%20Opened%20ID %20Type%20Status%20Summary%20Component%20Owner

但我想知道是否还有其他意见.

我有一个弹出的"等待窗口",我希望在活动结束时关闭.

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var app = UiApp.getActiveApplication();

var ss = SpreadsheetApp.getActiveSpreadsheet();

var sheet = getSheetWithSubmissions(ss);

// create UI app, this works fine

app = createWaitPleaseUI(sheet);

ss.show(app);

//simulated activity

Utilities.sleep(5000);

//this doesn't work despite being in the documentation

app.close();

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认为这是不可能的,但希望谷歌如果无法完成,就会从文档中删除它.

作为一种解决方法,我可以调出第二个GUI,说"工作完成,单击确定"然后它工作正常.

Answer 1

您必须返回app对象才能更新任何更改,甚至关闭.

return app.close()改为将最后一行改为.