JAX-WS:如何使SOAP响应返回HashMap对象

neo*_*neo 6 ajax jquery soap web-services jax-ws

所以我有一个简单的Web服务:

    @WebMethod(operationName="getBookList")
    public HashMap<Integer,Book> getBookList()
    {
        HashMap<Integer, Book> books = new HashMap<Integer,Book>();
         Book b1 = new Book(1,"title1");
         Book b2 = new Book(2, "title2");
         books.put(1, b1);
         books.put(2, b2);
        return books;
    }
Run Code Online (Sandbox Code Playgroud)

书类也很简单:

public class Book
{
    private int id;
    private String title;

    public int getId()
    {
        return id;
    }

    public String getTitle()
    {
        return title;
    }
    public Book(int id, String title)
    {
        id = this.id;
        title = this.title;
    }
}
Run Code Online (Sandbox Code Playgroud)

现在,当您在浏览器的测试仪中调用此Web服务时,我得到:

Method returned
my.ws.HashMap : "my.ws.HashMap@1f3cf5b"

SOAP Request
  ...
  ...

SOAP Response

<?xml version="1.0" encoding="UTF-8"?>
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
    <S:Body>
        <ns2:getBookListResponse xmlns:ns2="http://ws.my/">
            <return/>
        </ns2:getBookListResponse>
    </S:Body>
</S:Envelope>
Run Code Online (Sandbox Code Playgroud)


是否可以将返回的HashMap对象显示在<return>标记中,例如

<return>
     <Book1>
          id=1
          title=title1
     </Book1>
</return>
<return>
     <Book2>
          id=2
          title=title2
     </Book2>
</return>
Run Code Online (Sandbox Code Playgroud)

我想要返回标签中的值的原因是,从客户端,我在网页中使用jQuery AJAX来调用此Web服务,而我得到的响应XML只是空<return>标签.我如何从AJAX客户端获得真正的账面价值?

这是我的AJAX网络代码:

   $.ajax({
        url: myUrl, //the web service url
        type: "POST",
        dataType: "xml",
        data: soapMessage, //the soap message. 
        complete: showMe,contentType: "text/xml; charset=\"utf-8\""         

    });
function showMe(xmlHttpRequest, status)
{  (xmlHttpRequest.responseXML).find('return').each(function()
   { // do something
   }
}
Run Code Online (Sandbox Code Playgroud)

我用简单的hello world web服务进行了测试,并且工作正常.

gga*_*iao 3

为了帮助 JAXB,您可以将您的内容“包装”HashMap在一个类中,并使用 来@XmlJavaTypeAdapter将您的映射自定义序列化为 XML。

public class Response {

    @XmlJavaTypeAdapter(MapAdapter.class)    
    HashMap<Integer, Book> books;

    public HashMap<Integer, Book> getBooks() {
        return mapProperty;
    }

    public void setBooks(HashMap<Integer, Book> map) {
        this.mapProperty = map;
    }

}
Run Code Online (Sandbox Code Playgroud)

然后使用这个类作为你的返回值WebMethod

@WebMethod(operationName="getBookList")
    public Response getBookList()
    {
         HashMap<Integer, Book> books = new HashMap<Integer,Book>();
         Book b1 = new Book(1,"title1");
         Book b2 = new Book(2, "title2");
         books.put(1, b1);
         books.put(2, b2);
         Response resp = new Response();
         resp.setBooks(books);
         return resp;
    }
Run Code Online (Sandbox Code Playgroud)

毕竟,您需要实现您的适配器MapAdapter。有多种方法可以做到这一点,所以我建议您检查一下