Rag*_*ghu 2 sql oracle select grouping sqlxml
我在 Oracle 中的数据是这样的
NAME | DEP_VALUE | ID_DEP
Amy 1 AA1234
Bob 2 BB4321
Clara 1 CC5678
Clara 2 CC7890
John 1 JJ6543
John 2 JJ7865
John 3 JJ7654
Tom 1 TT0987
Tom 2 TT6541
Tom 3 TT4087
Tom 4 TT3409
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我需要以这种方式提取数据
NAME | DEP_VALUE | ID_DEP
Amy 1 AA1234
Bob 2 BB4321
Clara 1;2 CC5678;CC7890
John 1;2;3 JJ6543;JJ7865;JJ7654
Tom 1;2;3;4 TT0987;TT6541;TT4087;TT3409
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我的查询如下
SELECT name,
Rtrim(Xmlagg (Xmlelement (e, dep_value
|| ';')).extract ( '//text()' ), ','),
Rtrim(Xmlagg (Xmlelement (e, id_dep
|| ';')).extract ( '//text()' ), ',')
FROM (SELECT emp_name,
dep.dep_value,
dep.id_dep
FROM emp
inner join dep
ON emp.name = dep.name
WHERE id_name IN (SELECT name
FROM altname
WHERE id_emp IN (SELECT id_emp
FROM cnames
WHERE emp_lvl LIKE '%GGG%')))
GROUP BY name,
dep_value
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显示的结果是
NAME | DEP_VALUE | ID_DEP
Amy 1; AA1234;
Bob 2; BB4321;
Clara 1; CC5678;
Clara 2; CC7890;
John 1; JJ6543;
John 2; JJ7865;
John 3; JJ7654;
Tom 1; TT0987;
Tom 2; TT6541;
Tom 3; TT4087;
Tom 4; TT3409;
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如何提取第二个表中的数据?我的 sql 查询中的错误是什么?
听起来你想要GROUP BY name而不是GROUP BY name, dep_value
SELECT name,
Rtrim(Xmlagg (Xmlelement (e, dep_value
|| ';')).extract ( '//text()' ), ';'),
Rtrim(Xmlagg (Xmlelement (e, id_dep
|| ';')).extract ( '//text()' ), ';')
FROM (SELECT emp_name,
dep.dep_value,
dep.id_dep
FROM emp
inner join dep
ON emp.name = dep.name
WHERE id_name IN (SELECT name
FROM altname
WHERE id_emp IN (SELECT id_emp
FROM cnames
WHERE emp_lvl LIKE '%GGG%')))
GROUP BY name
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