如何在Lua-C API 5.2中创建类对象？

Question

我用Lua包装一个C函数,使用Lua-C API for Lua 5.2:

#include <lua.h>
#include <lauxlib.h>
#include <stdlib.h>
#include <stdio.h>

int foo_gc();
int foo_index();
int foo_newindex();
int foo_dosomething();
int foo_new();

struct foo {
  int x;
};

static const luaL_Reg _meta[] = {
    {"__gc", foo_gc},
    {"__index", foo_index},
    {"__newindex", foo_newindex},
    { NULL, NULL }
};
static const luaL_Reg _methods[] = {
    {"new", foo_new},
    {"dosomething", foo_dosomething},
    { NULL, NULL }
};

int foo_gc(lua_State* L) {
  printf("## __gc\n");
  return 0;
}
int foo_newindex(lua_State* L) {
  printf("## __newindex\n");
  return 0;
}
int foo_index(lua_State* L) {
  printf("## __index\n");
  return 0;
}
int foo_dosomething(lua_State* L) {
  printf("## dosomething\n");
  return 0;
}
int foo_new(lua_State* L) {
  printf("## new\n");

  lua_newuserdata(L,sizeof(Foo));
  luaL_getmetatable(L, "Foo");
    lua_setmetatable(L, -2); 

  return 1;
}

void register_foo_class(lua_State* L) {
    luaL_newlib(L, _methods); 
  luaL_newmetatable(L, "Foo");
  luaL_setfuncs(L, _meta, 0);
  lua_setmetatable(L, -2);
  lua_setglobal(L, "Foo");
}

当我运行这个Lua:

local foo = Foo.new()
foo:dosomething()

...我看到这个输出(有错误):

## new
## __index
Failed to run script: script.lua:2: attempt to call method 'dosomething' (a nil value)

我究竟做错了什么？谢谢

Answer 1

好的,搞定了.我不得不添加__index,并__metatable以Foo"新元表,如下图所示:

void register_foo_class(lua_State* L) {
  int lib_id, meta_id;

  /* newclass = {} */
  lua_createtable(L, 0, 0);
  lib_id = lua_gettop(L);

  /* metatable = {} */
  luaL_newmetatable(L, "Foo");
  meta_id = lua_gettop(L);
  luaL_setfuncs(L, _meta, 0);

  /* metatable.__index = _methods */
  luaL_newlib(L, _methods);
  lua_setfield(L, meta_id, "__index");  

  /* metatable.__metatable = _meta */
  luaL_newlib(L, _meta);
  lua_setfield(L, meta_id, "__metatable");

  /* class.__metatable = metatable */
  lua_setmetatable(L, lib_id);

  /* _G["Foo"] = newclass */
  lua_setglobal(L, "Foo");
}