使用List填充JTable

Question

如何使用具有对象类型的List中的值填充JTable.我的代码看起来像这样:

String[] columnNames = {"CLASS CODE",
        "TIME",
        "DAY",
        "ROOM",
        "PROFESSOR"};

    List<org.mine.ScheduleAttr> schedule = getStudSched(studNo);
    DefaultTableModel model = new DefaultTableModel();
    table.setModel(model);

    model.setColumnIdentifiers(columnNames);

我已经有了列,列表会来自schedule变量吗？考虑到这些列,我怎么能把它放到我的桌子上？

Answer 1

看看DefaultTableModel.您可以迭代List并为每行创建Object数组.

for (ScheduleAttr s : schedule) {
  Object[] o = new Object[5];
  o[0] = s.getX();
  o[1] = s.getY();
  o[2] = s.getZ();
  o[3] = s.getA();
  o[4] = s.getB();
  model.addRow(o);
}

Answer 2

你可以使用类似的东西(只是改变columns和values):

import java.awt.BorderLayout;
import java.util.ArrayList;
import java.util.List;

import javax.swing.JFrame;
import javax.swing.JScrollPane;
import javax.swing.JTable;
import javax.swing.table.DefaultTableModel;
import javax.swing.table.TableModel;

public class TestJFrame extends JFrame {
    private static final long serialVersionUID = 1L;

    public static void main(String[] args) {
        TestJFrame testJFrame = new TestJFrame();

        List<String> columns = new ArrayList<String>();
        List<String[]> values = new ArrayList<String[]>();

        columns.add("col1");
        columns.add("col2");
        columns.add("col3");

        for (int i = 0; i < 100; i++) {
            values.add(new String[] {"val"+i+" col1","val"+i+" col2","val"+i+" col3"});
        }

        TableModel tableModel = new DefaultTableModel(values.toArray(new Object[][] {}), columns.toArray());
        JTable table = new JTable(tableModel);
        testJFrame.setLayout(new BorderLayout());
        testJFrame.add(new JScrollPane(table), BorderLayout.CENTER);

        testJFrame.add(table.getTableHeader(), BorderLayout.NORTH);

        testJFrame.setVisible(true);
        testJFrame.setSize(200,200);
    }

}

在columns不需要像columns.toArray(),因为你已经有对象的数组,所以只是使用它.最后,为了使用您的列,指令如下所示: TableModel tableModel = new DefaultTableModel(values.toArray(new Object[][] {}), columnNames);