我是网络开发的真正初学者.以下代码在is_valid()检查时失败.但我不明白为什么:表单应该从POST数据中填充数据?
模型:
class Statement(models.Model):
text = models.CharField(max_length=255)
user = models.ForeignKey(User)
time = models.DateField()
views = models.IntegerField()
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的ModelForm:
class StatementForm(ModelForm):
class Meta:
model = Statement
widgets = {
'time':forms.HiddenInput(),
'user':forms.HiddenInput(),
'views':forms.HiddenInput(),
}
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查看功能:
def new(request):
if request.method == 'POST': # If the form has been submitted...
form = StatementForm(request.POST) # A form bound to the POST data
if form.is_valid():
stmt = form.save()
path = 'stmt/' + stmt.id
return render_to_response(path, {'stmt': stmt})
else:
c = {}
c.update(csrf(request))
loggedin_user = request.user
d = datetime.now()
form = StatementForm(request.POST, initial={'time': d.strftime("%Y-%m-%d %H:%M:%S"), 'user':loggedin_user, 'views':0})
return render_to_response('new_stmt.html', {'form': form, },context_instance=RequestContext(request))
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我找到了类似的主题,并尝试了很多.这就是我认为应该如何运作的方式.我真的需要建议.
sta*_*alk 10
您的模型的所有字段都是必需的.因此,form.is_valid()如果所有字段都填充了正确的值且未被消隐,则为True.你已经宣布领域time,user,views为隐藏字段.你确定,你已经填写了模板表格吗?此外,您可能想要自动标记字段time = models.DateField().修改您的模型字段,如
time = models.DateField(auto_now=True)`.
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在此之后,您不必自己以模板形式填写它.
您的视图必须在所有情况下都返回HttpResponse对象.如果您的表单无效,即if form.is_valid()将返回False,那么HttpResponse您的视图将不会返回任何对象.这可能是您失败的根源.添加else语句if form.is_valid():
from django.http import Http404
def new(request):
if request.method == 'POST': # If the form has been submitted...
form = StatementForm(request.POST) # A form bound to the POST data
if form.is_valid():
stmt = form.save()
path = 'stmt/' + stmt.id
return render_to_response(path, {'stmt': stmt})
else:
# Do something in case if form is not valid
raise Http404
else:
# Your code without changes
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