提升程序选项 - 获取部分中的所有条目

Question

根据文档,我可以解析样式中的配置文件:

 [main section]
 string = hello world. 
 [foo]
 message = Hi !

但我需要解析插件列表:

 [plugins]
 somePlugin. 
 HelloWorldPlugin
 AnotherPlugin
 [settings]
 type = hello world

如何获取插件部分中的字符串向量？

Answer 1

对于boost程序选项配置文件,如果该行没有声明某个部分,例如[settings],则需要采用name=value格式.对于您的示例,请将其写为以下内容:

[plugins]
name = somePlugin
name = HelloWorldPlugin
name = AnotherPlugin
[settings]
type = hello world

插件列表现在将对应于"plugins.name"选项,该选项需要是多音色选项.

下面是一个示例程序,它从settings.ini文件中读取上述设置:

#include <boost/program_options.hpp>
#include <iostream>
#include <fstream>
#include <string>
#include <vector>

int main()
{
  namespace po = boost::program_options;

  typedef std::vector< std::string > plugin_names_t;
  plugin_names_t plugin_names;
  std::string settings_type;

  // Setup options.
  po::options_description desc("Options");
  desc.add_options()
    ("plugins.name", po::value< plugin_names_t >( &plugin_names )->multitoken(),
                     "plugin names" )
    ("settings.type", po::value< std::string >( &settings_type ),
                      "settings_type" );

  // Load setting file.
  po::variables_map vm;
  std::ifstream settings_file( "settings.ini" , std::ifstream::in );
  po::store( po::parse_config_file( settings_file , desc ), vm );
  settings_file.close();
  po::notify( vm );    

  // Print settings.
  typedef std::vector< std::string >::iterator iterator;
  for ( plugin_names_t::iterator iterator = plugin_names.begin(),
                                      end = plugin_names.end();
        iterator < end;
        ++iterator )
  {
    std::cout << "plugin.name: " << *iterator << std::endl;
  }
  std::cout << "settings.type: " << settings_type << std::endl;

  return 0;
}

其中产生以下输出:

plugin.name: somePlugin
plugin.name: HelloWorldPlugin
plugin.name: AnotherPlugin
settings.type: hello world