Pea*_*Gen 2 .net c# if-statement while-loop c#-3.0
请查看以下代码
namespace Funny
{
class QuesionsAndAnswers
{
private double firstNumber;
private double secondNumber;
private double userAnswer;
private double computerAnswer;
private string operators;
private bool answerCorrect;
private bool enableDouble;
private double[] listOfNumbers;
private string[] listOfOperators;
private Random randomizer;
private static QuesionsAndAnswers qa;
private QuesionsAndAnswers()
{
randomizer = new Random();
listOfNumbers = new double[] { 1,2,3,4,5,6,7,8,9 };
listOfOperators = new string[] { "+", "-", "*", "/" };
}
public static QuesionsAndAnswers getQuesionsandAnswersInstance()
{
if (qa == null)
qa = new QuesionsAndAnswers();
return qa;
}
public string generateQuestions()
{
string result = "";
operators = listOfOperators[randomizer.Next(listOfOperators.Length)];
firstNumber = listOfNumbers[randomizer.Next(listOfNumbers.Length)];
secondNumber = listOfNumbers[randomizer.Next(listOfNumbers.Length)];
if ((operators.Equals("/")) && (enableDouble == false))
{
while (firstNumber % secondNumber == 0)
{
firstNumber = listOfNumbers[randomizer.Next(listOfNumbers.Length)];
}
result = firstNumber + operators + secondNumber;
}
else if (operators.Equals("-") && (firstNumber<secondNumber))
{
while (firstNumber > secondNumber)
{
firstNumber = listOfNumbers[randomizer.Next(listOfNumbers.Length)];
secondNumber = listOfNumbers[randomizer.Next(listOfNumbers.Length)];
}
result = firstNumber + operators + secondNumber;
}
return result;
}
public void setDoubleAnswers(bool check)
{
enableDouble = check;
}
}
}
Run Code Online (Sandbox Code Playgroud)
在这里,在generateQuestions()方法中,我试图生成一些数学问题.
如果运算符在" - "和firstNumber <secondNumber,那么应该重新生成数字(第一个数字和第二个数字)以确保答案不是负值.
并且,如果运算符是"/"并且布尔值为false,则它应该再次重新生成数字以确保答案(这意味着计算,例如2/1 = 2)不包含任何浮点数(这意味着它不应该生成像2/3这样的问题,因为答案包含浮点数).
在我的尝试中,上述两点都没有发生.它仍会产生意想不到的答案,有时甚至没有.这是为什么?请帮忙
请注意,我是一名Java开发人员,这是我的第一个主要C#项目.
好吧,它有时没有返回任何东西,因为除了你捕获的边缘情况之外,你永远不会设置result除了之外的任何东西"".
你的while陈述都是错误的.它应该是:
while ((firstNumber % secondNumber) != 0)
:
while (firstNumber < secondNumber)
Run Code Online (Sandbox Code Playgroud)
但是,为了提高效率,我不会这样做,while因为你可能会获得该属性所持有的长对子.如果数字是错误的方式,只需交换它们.
还有的珍贵稀少的情况下,其余的将是零,从你的电话号码选择(9/3,8/4,8/2,6/3,6/2,4/2,M/M和N/1是(我认为)详尽的清单).如果你想要一组更加扩展的方程式,我会采用另一种方式选择两个数字来进行多重处理,然后将第一个数字与结果交换.
例如,给定两个数字a = 3和b = 7,简单地做:
a = a * b;
Run Code Online (Sandbox Code Playgroud)
并且你有a = 21, b = 7保证给出一个整数乘数并提供方程式"21 / 7".
所以这个(伪代码)就是我要开始的:
# Get the random values.
op = random_from ("+-/*")
n1 = random_from ("123456789")
n2 = random_from ("123456789")
# For subtraction, make sure n1 >= n2.
if op = "-" and n1 < n2:
tmp = n1;
n1 = n2;
n2 = tmp;
# For division, make sure n1 is integral multiplier of n2.
if op = "/":
n1 = n1 * n2
# Return expression in ALL cases.
return n1 + op + n2
Run Code Online (Sandbox Code Playgroud)