可能重复:
计算两个Java日期实例之间的差异
如何获取Java中两个日期之间的天数?
什么是最好的方式?这是我得到的,但它不是最好的:
public static ConcurrentHashMap<String, String> getWorkingDaysMap(int year,
int month, int day){
int totalworkingdays=0,noofdays=0;
String nameofday = "";
ConcurrentHashMap<String,String> workingDaysMap =
new ConcurrentHashMap<String,String>();
Map<String,String> holyDayMap = new LinkedHashMap<String,String>();
noofdays = findNoOfDays(year,month,day);
for (int i = 1; i <= noofdays; i++) {
Date date = (new GregorianCalendar(year,month - 1, i)).getTime();
// year,month,day
SimpleDateFormat f = new SimpleDateFormat("EEEE");
nameofday = f.format(date);
String daystr="";
String monthstr="";
if(i<10)daystr="0";
if(month<10)monthstr="0";
String formatedDate = daystr+i+"/"+monthstr+month+"/"+year;
if(!(nameofday.equals("Saturday") || nameofday.equals("Sunday"))){
workingDaysMap.put(formatedDate,formatedDate);
totalworkingdays++;
}
}
return workingDaysMap;
}
public static int findNoOfDays(int year, int month, int day) {
Calendar calendar = Calendar.getInstance();
calendar.set(year, month - 1, day);
int days = calendar.getActualMaximum(Calendar.DAY_OF_MONTH);
return days;
}
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Adr*_*hum 22
我通常做这样的事情:
final long DAY_IN_MILLIS = 1000 * 60 * 60 * 24;
int diffInDays = (int) ((date1.getTime() - date2.getTime())/ DAY_IN_MILLIS );
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不需要外部lib,也很容易
更新:刚刚看到你想要"日期"之间,类似的方法适用:
//assume date1 < date2
List<Date> dateList = new LinkedList<Date>();
for (long t = date1.getTime(); t < date2.getTime() ; t += DAY_IN_MILLIS) {
dateList.add(new Date(t));
}
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当然,使用JODA时间或其他lib可能会让您的生活更轻松,但我不认为目前的方式难以实现
更新:重要提示!这仅适用于没有夏令时或类似调整的时区,或者您对"天数差异"的定义实际上意味着"24小时单位差异"