tug*_*erk 2 t-sql sql-server pivot sql-server-2008-r2
我有一个T-SQL查询,它查询包含搜索数据的表,并获取该搜索小时的搜索小时数和行数.
SELECT DATEPART(HOUR, aps.CreatedOn) AS SearchHour, COUNT(*) AS ItemCOUNT
FROM ASearches aps
GROUP BY DATEPART(HOUR, aps.CreatedOn)
ORDER BY SearchHour;
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如你所见,这不会产生很好的结果.但是,我知道如果我使用数据透视表并将小时作为列名,那会更好.我尝试过,但到目前为止我一直在失败.
知道怎么样?
像这样的东西:
SELECT *
FROM (SELECT DATEPART(HOUR, CreatedOn) AS SearchHour
FROM ASearches) aps
PIVOT (COUNT([SearchHour]) FOR SearchHour IN
( [0], [1], [2], [3], [4], [5],
[6], [7], [8], [9], [10], [11],
[12], [13], [14], [15], [16], [17],
[18], [19], [20], [21], [22], [23])) as pvt
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