无法使用Coreservice创建组件

Question

我正在尝试使用以下代码使用coreservice创建组件,当我执行exe时,我收到错误"无法找到uuid:""64c7e56a-161d-4698-a76b-7fd96227948d:Content".

我已经打开了链接到这个组件的模式,我也在那里看到了这个UUID.

截至目前我只是试图通过提供文件夹,架构,标题作为硬路径来创建组件.

如果你可以指导我如何在组件中添加字段值,那将是很好的.(例如,假设我的架构中有一个字段"Text",它链接到此组件,我想使用相同的程序在我的组件的这个字段中添加"This is the Text".

你可以帮我解决这个问题吗？

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using DctmToSDLMigration.SDLCoreServiceReference;

namespace DctmToSDLMigration
{
    class Program
    {
        static DctmToSDLMigration.SDLCoreServiceReference.SessionAwareCoreService2010Client client = new SessionAwareCoreService2010Client();
        static ReadOptions readoptions = new ReadOptions();
        static void CreateComponent()
        {
            try
            {
                string TargetFolderTcmId = "tcm:148-1263-2";
                string LinkSchemaTcmId = "tcm:148-11460-8";
                ComponentData CurrentMigrationComponent = client.GetDefaultData(ItemType.Component, TargetFolderTcmId) as ComponentData;                
                LinkToSchemaData SchemaToUse = new LinkToSchemaData();
                SchemaToUse.IdRef = LinkSchemaTcmId.ToString();
                CurrentMigrationComponent.Schema = SchemaToUse ;
                CurrentMigrationComponent.Title = "Test component";
                client.Create(CurrentMigrationComponent, readoptions);                
                Console.WriteLine(CurrentMigrationComponent.Id);
                Console.ReadLine();
            }
            catch (Exception e)
            {
                Console.WriteLine(e.Message);
                Console.ReadLine();
            }
        }
        static void Main(string[] args)
        {
            CreateComponent();
        }
    }
}

Answer 1

您需要设置组件的内容属性.

XmlDocument doc = new XmlDocument();

doc.LoadXml(string.Format(@"<Content xmlns='{0}'><Test>Hello</Test></Content>",     SchemaToUse.NamespaceUri));

CurrentMigrationComponent.Content = doc.DocumentElement;

XmlDocument doc = new XmlDocument();

doc.LoadXml(string.Format(@"<Content xmlns='{0}'><Test>Hello</Test></Content>",     SchemaToUse.NamespaceUri));

CurrentMigrationComponent.Content = doc.DocumentElement;