如何在SQL Server 2008 R2中将XML的一部分读取为XML

Question

我正在使用SQL Server 2008 R2,我的存储过程采用结构化XML,其中包含多个级别,如下所示:

DECLARE @XML xml = 
'<Main>
    <User id="1">
        <Departments isSingle="0">
            <Department id="1">Admin</Department>
            <Department id="2">HR</Department>
            <Department id="3">Development</Department>
        </Departments>
    </User>
    <User id="2">
        <Departments isSingle="1">
            <Department id="1">Admin</Department>            
        </Departments>
    </User>
</Main>'

从上面的例子我想为具有多个部门的用户获得2列(isSingle ="0"),其中第一列是用户id,第二列是整个<Departments>XML.

我可以使用以下查询获取用户标识但是如何将Departments部分作为XML获取:

SELECT
      T.C.value('(../@id)','int') AS UserID
    , T.C.value('(../Departments)[1]','nvarchar(max)') AS DepartmentsXML 
FROM 
@XML.nodes('/Main/User/Departments[@isSingle="0"]') AS T(C)

它不允许我xml用作数据类型代替nvarchar(max)

如果细节不明确,请告诉我,我会尽力改进.任何帮助表示赞赏.

Answer 1

你很接近 - 只需.query('.')用于你的第二栏:

SELECT
      T.C.value('(../@id)','int') AS UserID, 
      T.C.query('.') AS DepartmentsXML 
FROM 
@XML.nodes('/Main/User/Departments[@isSingle="0"]') AS T(C)

这将返回由.nodes()调用选择的XML片段,作为XML.