从一系列日期中获取最新日期

Question

我在下面列出了一系列日期

array(5) { 
    [0]=> string(19) "2012-06-11 08:30:49" 
    [1]=> string(19) "2012-06-07 08:03:54" 
    [2]=> string(19) "2012-05-26 23:04:04" 
    [3]=> string(19) "2012-05-27 08:30:00" 
    [4]=> string(19) "2012-06-08 08:30:55" 
}

并且想知道最近的日期:最接近今天的日期.

我怎样才能做到这一点？

Answer 1

使用max(),array_map()和strtotime().

$max = max(array_map('strtotime', $arr));
echo date('Y-m-j H:i:s', $max); // 2012-06-11 08:30:49

Answer 2

做一个循环,将值转换为日期,并将最新的值存储在var中.

$mostRecent= 0;
foreach($dates as $date){
  $curDate = strtotime($date);
  if ($curDate > $mostRecent) {
     $mostRecent = $curDate;
  }
}

类似的东西......你明白了如果你今天最想要的话:

$mostRecent= 0;
$now = time();
foreach($dates as $date){
  $curDate = strtotime($date);
  if ($curDate > $mostRecent && $curDate < $now) {
     $mostRecent = $curDate;
  }
}

Answer 3

按日期对数组进行排序,然后获取数组的前值.

$dates = array(5) { /** omitted to keep code compact */ }
$dates = array_combine($dates, array_map('strtotime', $dates));
arsort($dates);
echo $dates[0];

Answer 4

$dates = [
    "2012-06-11 08:30:49" 
    ,"2012-06-07 08:03:54" 
    ,"2012-05-26 23:04:04" 
    ,"2012-05-27 08:30:00" 
    ,"2012-06-08 08:30:55" 
];
echo date("Y-m-d g:i:s",max(array_map('strtotime',$dates)));