为什么在sql server 2005中使用xml时必须设置ARITHABORT?我试着研究为什么我要设置这个,但找不到告诉我原因的答案.只需要设置它.
这是我在取出SET ARITHABORT ON时获得的特定错误消息:
PARAMETER ERROR:INSERT LIST可能无法分配 - INSERT失败,因为以下SET选项的设置不正确:'ARITHABORT'.验证SET选项是否正确,以便与计算列和/或查询通知和/或xml数据类型方法的索引视图和/或索引一起使用.
我的存储过程在一个环境中使用odbc从asp.net调用很好.然后,当我将它移动到另一个时,我必须在存储过程的开头添加SET ARITHABORT ON.我在下面列出了存储过程的相关部分.以及调用它的代码.
CREATE PROCEDURE [dbo].[myproc]
@ruserid varchar(8),
@folder_list xml,
@insert_list xml
AS
SET NOCOUNT ON
SET ARITHABORT ON
DECLARE @rindex integer
DECLARE @errormsg nvarchar(4000)
DECLARE @folder_cnt integer
DECLARE @insert_cnt integer
SET @rindex = -1
-- temp table to hold inserts
CREATE TABLE #insert_list (rowidx integer IDENTITY(1,1), insertdesc varchar(96) COLLATE database_default, insertfolder integer)
-- temp table to hold folders
CREATE TABLE #folder_list (rowidx integer IDENTITY(1,1), folderdesc varchar(144) COLLATE database_default, insertfolder integer)
-- insert inserts to make sure data is compatible in type
BEGIN TRY
INSERT INTO #insert_list (insertdesc, insertfolder)
SELECT insert_list.listitem.value('@insertdesc', 'varchar(96)'), insert_list.listitem.value('@insertfolder', 'integer')
FROM @insert_list.nodes('/Root/Insert') AS insert_list(listitem)
END TRY
BEGIN CATCH
SET @errormsg = N'PARAMETER ERROR: INSERT LIST COULD NOT BE PARSED - ' + ERROR_MESSAGE()
RAISERROR(@errormsg, 16, 1)
RETURN
END CATCH
-- insert folders to make sure data is compatible in type
BEGIN TRY
INSERT INTO #folder_list (insertfolder, folderdesc)
SELECT folder_list.listitem.value('@insertfolder', 'integer'), folder_list.listitem.value('@folderdesc', 'varchar(144)')
FROM @folder_list.nodes('/Root/Folder') AS folder_list(listitem)
END TRY
BEGIN CATCH
SET @errormsg = N'PARAMETER ERROR: FOLDER LIST COULD NOT BE PARSED - ' + ERROR_MESSAGE()
RAISERROR(@errormsg, 16, 1)
RETURN
END CATCH
-- insert rows
BEGIN TRANSACTION
BEGIN TRY
INSERT INTO my_folder_request (ruserid)
VALUES ( @ruserid )
SET @rindex = SCOPE_IDENTITY()
INSERT INTO my_insert_request (rindex, insertdesc, insertfolder)
SELECT @rindex, #insert_list.insertdesc, #insert_list.insertfolder
FROM #insert_list
ORDER BY #insert_list.rowidx
INSERT INTO my_folder_desc (rindex, insertfolder, folderdesc)
SELECT @rindex, #folder_list.insertfolder, #folder_list.folderdesc
FROM #folder_list
ORDER BY #folder_list.rowidx
END TRY
BEGIN CATCH
IF @@TRANCOUNT > 0
ROLLBACK TRANSACTION
SET @errormsg = N'DATA INSERTION FAILED WITH MESSAGE - ' + ERROR_MESSAGE()
RAISERROR(@errormsg, 16, 1)
RETURN
END CATCH
IF @@TRANCOUNT > 0
COMMIT TRANSACTION
-- return result
SELECT @rindex AS rindex
DROP TABLE #insert_list
DROP TABLE #folder_list
GO
Run Code Online (Sandbox Code Playgroud)
致电代码
' build odbc command for inserting creation request
intRequestIndex = 0
cmdAddRequest = New System.Data.Odbc.OdbcCommand
cmdAddRequest.CommandType = CommandType.StoredProcedure
cmdAddRequest.CommandTimeout = 60
cmdAddRequest.CommandText = "{CALL myproc ( ?, ?, ?)}"
' add parameters to odbc command
cmdAddRequest.Parameters.Add("@ruserid", OdbcType.VarChar, 8).Value = SafeODBCParamString(m_strUID)
cmdAddRequest.Parameters.Add("@folder_list", OdbcType.NText).Value = System.Text.Encoding.Unicode.GetString(strmFolderList.ToArray())
cmdAddRequest.Parameters.Add("@insert_list", OdbcType.NText).Value = System.Text.Encoding.Unicode.GetString(strmInsertList.ToArray())
' run odbc command returning info about results
cmdAddRequest.Connection = Me.ODBCConnection()
Try
rdrRequestData = cmdAddRequest.ExecuteReader(CommandBehavior.CloseConnection)
Run Code Online (Sandbox Code Playgroud)
我在网上的书中想到这句话有点暗示:"当您在计算列或索引视图上创建或更改索引时,SET ARITHABORT必须为ON." 因此,nodes方法必须在内部或其他方面创建索引视图.但这只是一个有根据的猜测.
小智 5
这是从.Net客户端调用带有xml输入参数的存储过程时发现的ARITHABORT问题的解决方案。
using (var conn = new SqlConnection(dbConnectionString))
{
SqlCommand command = new SqlCommand("[stored procedure name here]", conn);
command.CommandType = CommandType.StoredProcedure;
command.Parameters.AddWithValue("@parameter_name", parameter_xml_value);
conn.Open();
SqlCommand arithabortCommand = new SqlCommand("SET ARITHABORT ON", conn);
arithabortCommand.ExecuteNonQuery();
command.ExecuteNonQuery();
conn.Close();
} // using (var conn = new SqlConnection(dbConnectionString))
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
21584 次 |
最近记录: |