在Shell脚本变量中搜索字符串

Question

我有一个shell脚本变量

$a = "Hello i am pass"

现在我想pass在变量中搜索" " $a.

if ["$a" == "pass"]; then
echo "`Success`" 
else 
echo "`fail`"
fi

请给我一个shell脚本,用于在上面的代码中搜索pass关键字.

Answer 1

试试这个,

#!/bin/bash
a="Hello i am pass";
if [ `echo $a | grep -c "pass" ` -gt 0 ]
then
  echo "Success"
else
  echo "Fail";
fi

Answer 2

flag=`echo $a|awk '{print match($0,"pass")}'`;

if [ $flag -gt 0 ];then

    echo "Success";
else
    echo "fail";

fi

Answer 3

这是一个更紧凑的方式来写这个:

echo "$a" | grep "pass" && echo "Found." || echo "Not found."

您可以使用括号来放入多个指令而不是简单的echo:

echo "$a" | grep "pass" && (echo "Found.";exit 0) || (echo "Not found.";exit 1)