线程"main"中的异常java.security.AccessControlException:访问被拒绝(java.util.PropertyPermission*read,write)

Question

我正在尝试运行一个用java rmi开发的桌面应用程序.当我试图在eclipse中执行此应用程序时,我收到以下错误.请任何人提前帮助我.

Exception in thread "main" java.security.AccessControlException: access denied (java.util.PropertyPermission * read,write)
    at java.security.AccessControlContext.checkPermission(Unknown Source)
    at java.security.AccessController.checkPermission(Unknown Source)
    at java.lang.SecurityManager.checkPermission(Unknown Source)
    at java.lang.SecurityManager.checkPropertiesAccess(Unknown Source)
    at java.lang.System.getProperties(Unknown Source)
    at .HeadOfficeManager.Manager.main(Manager.java:103)

这是代码.

public static void main(String args[])
{
    Manager frame = new Manager();
    frame.setVisible(true);
    // frame.show(); old 1.4

    // Create and install a security manager
    if (System.getSecurityManager()== null)
    {
        System.setSecurityManager(new RMISecurityManager());
    }
    try
    {
        Properties prop = System.getProperties();
        String httpPath = prop.getProperty("HTTPPath");
        new ClassFileServer(80, httpPath);
    }
    catch (IOException e)
    {}

    try
    {
        java.rmi.registry.LocateRegistry.createRegistry(1099);
        System.out.println("RMI registry ready.");
    }
    catch (Exception e)
    {
        System.out.println("Exception starting RMI registry:");
        e.printStackTrace();
    }
    try
    {
        RMIHandler = new ManagerRMIHandler();

        // Bind the remote object's stub in the registry
        Registry registry = LocateRegistry.getRegistry();
        registry.rebind("HeadOfficeManager", RMIHandler);

        System.err.println("Server ready");
    }
    catch (Exception e)
    {
        System.err.println("Server exception: " + e.toString());
        e.printStackTrace();
    }

Answer 1

1. 右键单击eclipse中的应用程序,然后单击运行配置.
2. 添加虚拟机参数为 -Djava.security.policy =java.policy.applet.
3. 创建一个文件,将其命名为java.policy.applet.

4. 在该文件中添加以下行.

   grant  
   {  
       permission java.security.AllPermission;  
   };
   

5. 保存并运行应用程序.

这将为您的Java应用程序提供所有安全权限.