如何从两个SQL表中获取不匹配的记录？

Question

我想从SQL中的两个表中获取不匹配的记录,表结构如下:

表格1

Id      Name
1       Prashant
2       Ravi
3       Gaurav
5       Naween
7       Sachin

表2

Id      Name
1       Prashant
2       Ravi
4       Alok
6       Raja

我想要的输出是

Id      Name
3       Gaurav
4       Alok
5       Naween
6       Raja
7       Sachin

在SQL中获取所需输出的查询是什么？

Answer 1

我认为joeslice的回答只会给出一半的结果.你需要联合另一个表.或者,您可以执行完全外部联接.

select a.Id, a.Name from Table1 a left outer join Table2 b on a.Name = b.Name where b.Id is null
UNION ALL
select a.Id, a.Name from Table2 a left outer join Table1 b on a.Name = b.Name where b.Id is null

Answer 2

create table #t1 (Id int, name varchar(50)) 
create table #t2 (Id int, name varchar(50)) 

insert #t1 values (1,       'Prashant')
insert #t1 values (2,      'Ravi')
insert #t1 values (3,       'Gaurav')
insert #t1 values (5,       'Naween')
insert #t1 values (7,       'Sachin')

insert #t2 values (1,       'Prashant')
insert #t2 values (2,       'Ravi')
insert #t2 values (4,       'Alok')
insert #t2 values (6,       'Raja')

select isnull(#t1.id, #t2.id), isnull(#t1.name,#t2.name)  from #t1 
full outer join #t2 on #t1.id = #t2.id
where #t2.Id is null or #t1.id is null

结果:

3   Gaurav
5   Naween
7   Sachin
4   Alok
6   Raja

Answer 3

Select Id, Name
from Table1
where Id not in (select Id from Table2)
UNION 
Select Id, Name
from Table2
where Id not in (select Id from Table1)