Data.Text在打印出来进行调试之前我一直在解压缩实例,并且认为只是用Text.Printf它.不幸的是,我无法让它发挥作用:
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE ScopedTypeVariables #-}
import Data.Text
import Text.Printf
--instance PrintfArg Text where
-- toUPrintf = toUPrintf . unpack
main :: IO ()
main = do
let input :: Text = "abc"
printf "Input: %s\n" input
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错误:
src/Main.hs:12:3:
No instance for (PrintfArg Text)
arising from a use of `printf'
Possible fix: add an instance declaration for (PrintfArg Text)
In a stmt of a 'do' block: printf "Input: %s" input
In the expression:
do { let input :: Text = "abc";
printf "Input: %s" input }
In an equation for `main':
main
= do { let input :: Text = ...;
printf "Input: %s" input }
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取消注释实例声明后:
src/Main.hs:7:7:
`toUPrintf' is not a (visible) method of class `PrintfArg'
src/Main.hs:7:19: Not in scope: `toUPrintf'
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有任何想法吗?
EDITED
正如所建议的,试过TH,仍然没有去:
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE ScopedTypeVariables #-}
{-# LANGUAGE TemplateHaskell #-}
import Data.Text
import Language.Haskell.TH
import Text.Printf
runQ [d| instance PrintfArg Text where toUPrintf = toUPrintf . unpack|]
main :: IO ()
main = do
let input :: Text = "abc"
printf "Input: %s\n" input
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错误:
src/Main.hs:9:40:
'toUPrintf' is not a (visible) method of class 'PrintfArg'
src/Main.hs:9:52: Not in scope: 'toUPrintf'
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救命!令人惊讶的是,根据默认情况下使用Data.Text的所有建议,这不是开箱即用的.