如何检查2个旋转矩形之间的交点？

Question

有人可以解释如何检查一个旋转的矩形是否与其他矩形相交？

Answer 1

1. 对于两个多边形中的每条边,检查它是否可用作分隔线.如果是这样,你就完成了:没有交集.
2. 如果没有找到分隔线,则有一个交叉点.

/// Checks if the two polygons are intersecting.
bool IsPolygonsIntersecting(Polygon a, Polygon b)
{
    foreach (var polygon in new[] { a, b })
    {
        for (int i1 = 0; i1 < polygon.Points.Count; i1++)
        {
            int i2 = (i1 + 1) % polygon.Points.Count;
            var p1 = polygon.Points[i1];
            var p2 = polygon.Points[i2];

            var normal = new Point(p2.Y - p1.Y, p1.X - p2.X);

            double? minA = null, maxA = null;
            foreach (var p in a.Points)
            {
                var projected = normal.X * p.X + normal.Y * p.Y;
                if (minA == null || projected < minA)
                    minA = projected;
                if (maxA == null || projected > maxA)
                    maxA = projected;
            }

            double? minB = null, maxB = null;
            foreach (var p in b.Points)
            {
                var projected = normal.X * p.X + normal.Y * p.Y;
                if (minB == null || projected < minB)
                    minB = projected;
                if (maxB == null || projected > maxB)
                    maxB = projected;
            }

            if (maxA < minB || maxB < minA)
                return false;
        }
    }
    return true;
}

有关更多信息,请参阅此文章:2D多边形碰撞检测 - 代码项目

注意:该算法仅适用于凸多边形,以顺时针或逆时针顺序指定.

Answer 2

在javascript中,完全相同的算法是(为方便起见):

/**
 * Helper function to determine whether there is an intersection between the two polygons described
 * by the lists of vertices. Uses the Separating Axis Theorem
 *
 * @param a an array of connected points [{x:, y:}, {x:, y:},...] that form a closed polygon
 * @param b an array of connected points [{x:, y:}, {x:, y:},...] that form a closed polygon
 * @return true if there is any intersection between the 2 polygons, false otherwise
 */
function doPolygonsIntersect (a, b) {
    var polygons = [a, b];
    var minA, maxA, projected, i, i1, j, minB, maxB;

    for (i = 0; i < polygons.length; i++) {

        // for each polygon, look at each edge of the polygon, and determine if it separates
        // the two shapes
        var polygon = polygons[i];
        for (i1 = 0; i1 < polygon.length; i1++) {

            // grab 2 vertices to create an edge
            var i2 = (i1 + 1) % polygon.length;
            var p1 = polygon[i1];
            var p2 = polygon[i2];

            // find the line perpendicular to this edge
            var normal = { x: p2.y - p1.y, y: p1.x - p2.x };

            minA = maxA = undefined;
            // for each vertex in the first shape, project it onto the line perpendicular to the edge
            // and keep track of the min and max of these values
            for (j = 0; j < a.length; j++) {
                projected = normal.x * a[j].x + normal.y * a[j].y;
                if (isUndefined(minA) || projected < minA) {
                    minA = projected;
                }
                if (isUndefined(maxA) || projected > maxA) {
                    maxA = projected;
                }
            }

            // for each vertex in the second shape, project it onto the line perpendicular to the edge
            // and keep track of the min and max of these values
            minB = maxB = undefined;
            for (j = 0; j < b.length; j++) {
                projected = normal.x * b[j].x + normal.y * b[j].y;
                if (isUndefined(minB) || projected < minB) {
                    minB = projected;
                }
                if (isUndefined(maxB) || projected > maxB) {
                    maxB = projected;
                }
            }

            // if there is no overlap between the projects, the edge we are looking at separates the two
            // polygons, and we know there is no overlap
            if (maxA < minB || maxB < minA) {
                CONSOLE("polygons don't intersect!");
                return false;
            }
        }
    }
    return true;
};

希望这有助于某人.

Answer 3

如果有人感兴趣的话,这是Java中的相同算法.

boolean isPolygonsIntersecting(Polygon a, Polygon b)
{
    for (int x=0; x<2; x++)
    {
        Polygon polygon = (x==0) ? a : b;

        for (int i1=0; i1<polygon.getPoints().length; i1++)
        {
            int   i2 = (i1 + 1) % polygon.getPoints().length;
            Point p1 = polygon.getPoints()[i1];
            Point p2 = polygon.getPoints()[i2];

            Point normal = new Point(p2.y - p1.y, p1.x - p2.x);

            double minA = Double.POSITIVE_INFINITY;
            double maxA = Double.NEGATIVE_INFINITY;

            for (Point p : a.getPoints())
            {
                double projected = normal.x * p.x + normal.y * p.y;

                if (projected < minA)
                    minA = projected;
                if (projected > maxA)
                    maxA = projected;
            }

            double minB = Double.POSITIVE_INFINITY;
            double maxB = Double.NEGATIVE_INFINITY;

            for (Point p : b.getPoints())
            {
                double projected = normal.x * p.x + normal.y * p.y;

                if (projected < minB)
                    minB = projected;
                if (projected > maxB)
                    maxB = projected;
            }

            if (maxA < minB || maxB < minA)
                return false;
        }
    }

    return true;
}