Jor*_*anc 7 mysql sql messaging
我正在使用具有两个表的消息传递系统和另一个包含用户信息的表.
对话可以在2个或更多用户之间.每个会话都有一个UID,用户之间交换的每条消息都标有该会话UID.
以下是表格:
conversation_list:此表中的每一行都链接user_id和conversation_id,它还包含用户上次查看对话的时间.
`id` -> unique ID, autoincremented
`user_id` -> This contains the user associated with the conversation.
`conversation_id` -> This contains the UID of the conversation
`date_lastView` -> This field has the time that the user viewed the conversation last
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conversation_messages :此表中的每一行都包含一条消息
`id` -> unique ID, autoincremented
`user_id` -> This contains the user that sent the message.
`conversation_id` -> This contains the UID of the conversation
`date_created` -> This contains the time when the message was posted
`message` -> This contains the message
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users :此表中的每一行都包含一个用户
`User_ID` -> UID of the user
`FirstName` -> This contains the first name of the user
`LastName` -> This contains the last name of the user
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我已经有一个SQL查询来获取每个对话的最后一条消息.这里是 :
SELECT *
FROM conversation_messages AS m
JOIN
(SELECT mx.conversation_id,
MAX(mx.date_created) AS MaxTime
FROM conversation_messages AS mx
GROUP BY mx.conversation_id) AS mx ON m.conversation_id = mx.conversation_id
AND m.date_created = mx.MaxTime
JOIN
(SELECT mu.conversation_id
FROM conversation_list AS mu
WHERE mu.user_id = :USER_ID_CONNECTED
GROUP BY mu.conversation_id) AS mux ON m.conversation_id = mux.conversation_id
JOIN conversation_list AS mu ON m.conversation_id = mu.conversation_id
GROUP BY mu.conversation_id
ORDER BY m.date_created DESC
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我现在想要添加到这个完美工作的查询返回的能力:
date_creaded大于date_lastView登录用户的数量)User_ID每个对话中的每个用户,并按照他们上次在对话中发布消息的时间排序.FirstName和LastName用户.我尝试了一些事情,但我真的不成功,所以我现在要求SO社区提供宝贵的帮助.
所有这些只能显示登录用户参与的对话.
它有帮助,我创建了一个SQLFiddle
小智 3
用户对话中未读消息的数量(此处为用户#6):
SELECT l.conversation_id, count(*)
FROM conversation_list l
JOIN conversation_messages m ON m.conversation_id = l.conversation_id AND m.date_created > l.date_lastview
WHERE l.user_id = 6
GROUP BY l.conversation_id
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按上次活动排序的对话参与者:
SELECT conversation_id, user_id, max(date_created) as last_active
FROM conversation_messages
GROUP BY conversation_id, user_id
ORDER BY conversation_id, last_active
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第三个查询应该与第二个查询一样,只是在 上再加入一个表user_id,对吗?
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