在Django中使用ContentType过滤2个模型

Mod*_*esq 4 django django-models django-admin

我有2个配置文件模型.我正在创建一个"参加者"对象.如何在2个配置文件之间进行过滤?

class Profile1(models.Model):
    user = models.ForeignKey(User, null=True, unique=True)

class Profile2(models.Model):
    user = models.ForeignKey(User, null=True, unique=True)

class Attendee(models.Model):
    event = models.ForeignKey(Event)
    # This filters through everything... How do I filter down just to the 2 profile objects?
    content_type = models.ForeignKey(ContentType)
    object_id = models.PositiveIntegerField()
    profile = generic.GenericForeignKey('content_type', 'object_id')
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谢谢你的帮助!

Ahs*_*san 9

由于ContentType模型有三个字段app_label,modelname.因此,您可以轻松过滤这些字段.

attendees = Attendee.objects.filter(content_type__model = 'Profile1')
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Boe*_*ern 7

我会去

from django.contrib.contenttypes.models import ContentType
...

Attendee.objects.filter(
   content_type=ContentType.objects.get_for_model(Profile1))
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以避免重构类名后比较字符串和错误。