Python尝试除了最后:语法错误无效(这段代码有什么问题？)

Question

我试图在下面的函数中使用finally,但是,Python报告了一个语法错误.我确定我做的很傻,但我似乎无法发现它......

片段如下:

# Store ids with key
# Returns GUID (used to clear table after words)
def storeIdsInTemporaryTable(dbinfo, id_list):
    conn = dbinfo['db_connection']

    guid = genutils.getGUID()
    orig_tableinfo = dbinfo['table']
    orig_datarows = dbinfo['datarows']

    metadata = dbinfo['metadata']

    sql = "INSERT INTO temporary_data_key (key) VALUES ({0}) RETURNING id".format(guid)
    key_id = executeSQLonDbConnection(dbinfo, sql, return_field='id')

    tableinfo = Table('temporary_data', metadata, autoload=True)
    datarows = []

    for id_value in id_list:
        datarows.append( { 'key_id': key_id, 'id_value': id_value} )

    try:
        insertToDb(dbinfo)
    except:
        guid = None # to indicate an error occured
        if key_id:
            conn.execute("DELETE FROM temporary_data_key WHERE key={0}".format(guid)

    finally:
        dbinfo['table'] = orig_tableinfo
        dbinfo['datarows'] = orig_datarows

    return guid

是什么导致语法错误？

顺便说一句,我知道我需要在事务中包装两个插入,但由于某种原因,我无法使事务工作(SQLALchemy抛出与事务相关的错误) - 所以那是另一个问题的另一个时间..

[[编辑]]

异常错误(现已修复)是​​:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/path/to/script.py", line 1632
    finally:
          ^
SyntaxError: invalid syntax

Answer 1

你使用的是Python <2.5吗？尝试除了最后只是在2.5中添加,然后你必须包装尝试除了最后尝试.

Answer 2

您在通话中错过了一个右括号execute().它应该是:

conn.execute("DELETE FROM temporary_data_key WHERE key={0}".format(guid))

代替:

conn.execute("DELETE FROM temporary_data_key WHERE key={0}".format(guid)