OpenCV C++使用cv :: Moments

Question

我尝试使用OpenCV C++的cv :: Moments找到质心.无论我提交什么论点,我收到的全部都是零.显然,我做了一件非常错误的事情.输出代码:

23 of 500 elements in unit 3
point values 2.976444 18.248287
matrix size 23
moments 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000
moments 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000

和代码:

printf("%d of %d elements in unit %d\n",k,number_of_features,i);
cv::Mat x(k, 1, cv::DataType<cv::Point2f>::type);
k=0;
for(int j=0;j <number_of_features;j++) {
    if(i  == labels.at<int>(j)) {
        x.at<cv::Point2f>(k++) = samples.at<cv::Point2f>(i); 
    }
}
printf("point values %f %f\n", x.at<cv::Point2f>(0).x,x.at<cv::Point2f>(0).y);
cv::Size s=x.size();
printf("matrix size %d\n",s.height);
cv::Moments m=cv::moments(x);
printf("moments %f %f %f %f %f %f %f %f\n",m.m00,m.m01,m.m20,m.m11,m.m02,m.m30,m.m21,m.m03);
double h[7];
cv::HuMoments(m,h);
printf("moments %f %f %f %f %f %f %f\n",h[0],h[1],h[2],h[3],h[4],h[5],h[6]);

奇怪的是,我无法从Google找到任何相同的代码示例.我所看到的只是C风格的方法.

Answer 1

利用时刻找到一个质心有点矫枉过正.您可以使用以下算法来执行此操作:

sumX = 0; sumY = 0;
size = array_points.size;
if(size > 0){

    foreach(point in array_points){
        sumX += point.x;
        sumY += point.y;
    }

 centroid.x = sumX/size;
 centroid.y = sumY/size;
}

或者在Opencv的boundingRect的帮助下:

//pseudo-code:

Rect bRect = Imgproc.boundingRect(array_points);

centroid.x = bRect.x + (bRect.width / 2);
centroid.y = bRect.y + (bRect.height / 2);