获得联系人绩效问题

Question

我想获得Android设备的联系人.我在这里找到了很好的示例代码

但是,当尝试使用该代码进行填充ListActivity时ArrayAdapter,需要花费大量时间 - 在galaxy s2上花费大约4秒钟,在旧设备上花费更多时间.我需要改善这种表现.我认为实现Cursor将包含多个维度Cursor,并SimpleCursorAdapter用作列表适配器.
我发现这种方法几乎没有问题:

• 我不知道如何在特定位置获得物品.
• 每个游标都有不同的列.

有更好/更简单的方法吗？

编辑:

这是我的代码:

public List<ContactData> readContacts(){
    ContentResolver cr = getContentResolver();
    List<ContactData> cd = new ArrayList<ContactData>();
    Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
           null, null, null, ContactsContract.Contacts.DISPLAY_NAME);

    if (cur.getCount() > 0) {
       while (cur.moveToNext()) {
           String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
           String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
           if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {

               // get the phone number
               Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,
                                      ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = ?",
                                      new String[]{id}, null);
               while (pCur.moveToNext()) {
                     String phone = pCur.getString(
                            pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                     if (!Utils.isEmpty(phone)) {
                         cd.add(new ContactData(id, name, phone));
                     }
               }
               pCur.close();


           }
       }
  }
    return cd;
}

编辑2:

设法通过将其更改为只有一个查询来修复它:

public List<ContactData> readContacts(){
    ContentResolver cr = getContentResolver();
    List<ContactData> cd = new ArrayList<ContactData>();
               Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
                       new String[]{ContactsContract.CommonDataKinds.Phone._ID,ContactsContract.CommonDataKinds.Phone.NUMBER,ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME_PRIMARY},
                       ContactsContract.CommonDataKinds.Phone.NUMBER + " IS NOT NULL",
                                      null, 
                                      ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME_PRIMARY);
               while (pCur.moveToNext()) {
                     String phone = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                     String id = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone._ID));
                     String name = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME_PRIMARY));
                         ContactData cd1 = contactDataProvider.get();
                         cd1.id = id;
                         cd1.name = name;
                         cd1.phone = phone;
                         cd.add(cd1);
               }
               pCur.close();
    return cd;
}

Answer 1

您可以在获取电话号码的同时获取姓名和 ID：

String[] PROJECTION=new String[] {Contacts._ID, Contacts.DISPLAY_NAME, Phone.NUMBER};
Cursor pCur = cr.query(Phone.CONTENT_URI, PROJECTION, Phone.CONTACT_ID +" = ?",
                                      new String[]{id}, null);

这消除了每行子查询。