将千字节,兆字节等转换为R中的字节

Question

R中是否有标准函数来转换表示字节数的字符串,例如

• 11855276K
• 113M
• 2.40g的

到整数个字节？

我humanReadable在包gdata中遇到过,但这反过来又转换了.我知道我可以解析字符串,然后自己做数学,但我想知道是否已存在某些东西.

Answer 1

一个简单的功能:

x <- c("11855276K", "113M", "2.40G", "1234")

convb <- function(x){
  ptn <- "(\\d*(.\\d+)*)(.*)"
  num  <- as.numeric(sub(ptn, "\\1", x))
  unit <- sub(ptn, "\\3", x)             
  unit[unit==""] <- "1" 

  mult <- c("1"=1, "K"=1024, "M"=1024^2, "G"=1024^3)
  num * unname(mult[unit])
}

convb(x)
[1] 12139802624   118489088  2576980378        1234

您可能需要添加其他单位和转换,例如太字节.

Answer 2

优秀的fs 软件包fs_bytes具有可以双向处理此问题的功能。

## Create some number of bytes of differing units, and "convert" to fs_bytes
sizes <- c("11855276K", "113M", "2.40G", "1234") |>
  fs::fs_bytes()

## It picks sensible human-readable default units for printing
sizes
## 11.31G 113M   2.4G   1.21K

## The data is stored as numeric
str(sizes)
## 'fs_bytes' num [1:4] 11.31G 113M 2.4G 1.21K

## As a result, you can perform numeric operations on them
sum(sizes)
## 13.8G

## Use as.numeric to print the values as bytes
as.numeric(sizes)
## [1] 12139802624   118489088  2576980378        1234