使用jquery验证的远程功能

Question

我试图找出如何解决这个问题:

$('#username').blur(function(){
    $.post('register/isUsernameAvailable', 
           {"username":$('#username').val()}, 
           function(data){
               if(data.username == "found"){
                   alert('username already in use');
               }
           }, 'json');
});

接近这个:

rules: {
        username: {
            minlength: 6,
            maxlength: 12,
            remote: {
                url: 'register/isUsernameAvailable',
                type: 'post',
                data: {
                    'username': $('#username').val()
                } 

            }
        }

但是我很难完成它.我想要的是代替警报,让它显示错误消息,但我可以在实际的jquery验证消息中设置消息.

http://docs.jquery.com/Plugins/Validation/Methods/remote#options

更新:

出于某种原因,它没有把它作为一个POST做它作为GET请求并且不确定原因.这是更新的代码:

rules: {
        username: {
            minlength: 6,
            maxlength: 12,
            remote: {
                url: 'register/isUsernameAvailable',
                dataType: 'post',
                data: {
                    'username': $('#username').val()
                },
                success: function(data) {
                    if (data.username == 'found')
                    {
                        message: {
                            username: 'The username is already in use!'
                        }
                    }
                }

            }
        },

更新2:

现在我正在回到某个地方,我正在收到POST请求.我还有两个问题.其中一个原因是,要完成另一个POST请求,用户必须刷新表单.最后一个问题是,如果找到返回的用户名,则不会显示错误消息.

rules: {
        username: {
            minlength: 6,
            maxlength: 12,
            remote: {
                type: 'post',
                url: 'register/isUsernameAvailable',
                data: {
                    'username': $('#username').val()
                },
                dataType: 'json',
                success: function(data) {
                    if (data.username == 'found')
                    {
                        message: {
                            username: 'The username is already in use!'
                        }
                    }
                }

            }
        },

更新:

public function isUsernameAvailable()
{
    if ($this->usersmodel->isUsernameAvailable($this->input->post('username')))
    {
        return false;
    }
    else
    {
        return true;
    }        
}

更新4:

控制器:

public function isUsernameAvailable()
{
    if ($this->usersmodel->isUsernameAvailable($this->input->post('username')))
    {
        return false;
    }
    else
    {
        return true;
    }        
}

public function isEmailAvailable()
{
    if ($this->usersmodel->isEmailAvailable($this->input->post('emailAddress')))
    {
        return false;
    }
    else
    {
        return true;
    }        
}

模型:

/**
 * Check if username available for registering
 *
 * @param   string
 * @return  bool
 */
function isUsernameAvailable($username)
{
    $this->db->select('username');
    $this->db->where('LOWER(username)=', strtolower($username));
    $query = $this->db->get($this->usersTable);
    if ($query->num_rows() == 0)
    {
        return true;
    }
    else
    {
        return false;
    }
}

/**
 * Check if email available for registering
 *
 * @param   string
 * @return  bool
 */
function isEmailAvailable($email)
{
    $this->db->select('email');
    $this->db->where('LOWER(email)=', strtolower($email));
    $query = $this->db->get($this->usersTable);
    if($query->num_rows() == 0)
    {
        return true;
    }
    else
    {
        return false;
    }
}

Answer 1

完成此操作的最简单方法是简单地返回true,将错误消息作为字符串或false从服务器端资源返回.根据远程的jQuery验证文档:

响应被评估为JSON,对于有效元素必须为true,并且对于无效元素,可以是任何false,undefined或null,使用默认消息; 或者一个字符串,例如."该名称已被采用,请尝试使用peter123"以显示为错误消息.

这意味着如果您可以更改服务器端代码以true在验证成功时返回,或者在验证失败的情况下更改错误消息("用户名已在使用中"),您可以编写以下远程规则:

remote: {
    type: 'post',
    url: 'register/isUsernameAvailable',
    data: {
        'username': function () { return $('#username').val(); }
    },
    dataType: 'json'
}

您也可以简单地返回true或false从服务器端资源返回并在客户端上定义错误消息.在这种情况下,您将拥有上述规则,然后是messages对象中的属性:

messages: {
    username: {
        remote: "username already in use"
    }
}

Answer 2

我知道为时已晚,但这可以帮助其他人.

远程方法是为了接收一个Json字符串,所以你的服务器端应该返回这样的方法...

echo(json_encode(true)); // if there's nothing matching
echo(json_encode(false));

这是我在尝试验证用户昵称时编写的JS代码示例.

$(document).ready(function(){
            $('#form').validate({
            rules: {
                user_nickname: {
                    remote: {
                        url: "available.php",
                        type: "post",
                        data: {
                          user_nickname: function() {
                            return $( "#user_nickname" ).val();
                          }
                        }
                      }               
                }
            },
            messages:{
                user_nickname: {
                    remote: "Username already taken"
                }
            }
        });});

希望它对某人有所帮助,它帮助了我.

Answer 3

我意识到这很旧，但我也很难让它正常工作，并想分享对我有用的东西。

客户端表单验证代码：

$('#frmAddNew').validate({
onkeyup: false,
rules: {
    ADID: {
        required: true,
        alphanumeric: true,
        maxlength: 10,
        remote: {
            url: "ADIDValidation.cshtml",
            type: "post",
            dataType: "json",
            dataFilter: function (data) {
                if (data) {
                    var json = $.parseJSON(data);
                    if (json[0]) {
                        return JSON.stringify(json[0].valid) /* will be "true" or whatever the error message is */
                    }
                }
            },
            complete: function (data) {
               /* Additional code to run if the element passes validation */
                if (data) {
                    var json = $.parseJSON(data.responseText);
                    if (json[0]) {
                        if (json[0].valid === "true") {
                            $('#FirstName').val(json[0].FirstName);
                            $('#LastName').val(json[0].LastName);
                        }
                    }
                }
            }
        }
    }
},
messages: {
    ADID: {
        required: "Please Enter an ADID of the Employee",
        alphanumeric: "The ADID Can Only Contain Letters and Numbers",
        maxlength: "ADID For User's Current Permissions Must Be 10 Characters or Less"
    }
},
submitHandler: function (form) {
    form.submit();
},
errorContainer: $('section.errorCon'),
errorLabelContainer: $('ol', 'section.errorCon'),
wrapper: 'li',
showErrors: function (errors) {
    var error = this.numberOfInvalids();
    var message = error == 1
        ? 'You missed 1 field:'
        : 'You missed ' + error + ' fields:';
    $('section.errorCon h3').html(message);
    this.defaultShowErrors();
}
});

ADIDValidation.cshtml 的服务器端代码（我使用的是 Razor 网页）：

@{

Layout = null;

if(IsPost)
{
    var db = Database.Open("<enter connection name>");
    var sql = "<enter sql or stored procedure>";
    var strADID = Request["ADID"];

    var result = db.Query(sql, strADID);
    IEnumerable<dynamic> response;

    if(result.Any()) 
    {
        @* "true" indicates the element passes validation. Additional data can be passed to a callback function *@
        response = result.Select(x => new
        {
            valid = "true",
            FirstName = x.FirstName,
            LastName = x.LastName
        });
    }

    else
    {
        @* The element did not pass validation, the message below will be used as the error message *@
        response = new[] {
            new {valid = "The Employee's ADID '" + strADID.ToString() + "' Is Not Valid. Please Correct and Resubmit"}
        };
    }

    Json.Write(response, Response.Output);
}
}

Answer 4

好吧，我具体不知道你的插件概念，但我猜你希望它检查该插件是否用户名大于 6 或小于 12。从你的 jQuery 核心示例（不带插件）来看，它就像添加一样简单这个概念有一点 if-else。

$('#username').blur(function(){
    if($('#username').val().length < 6 || $('#username').val().length > 12)
    {
        alert('Username must be between 6 and 12 characters');
    }
    else
    {
       $.post('register/isUsernameAvailable', 
              {"username":$('#username').val()}, 
              function(data){
                  if(data.username == "found"){
                      alert('username already in use');
                  }
              }, 'json');
    }
});