ASM到C - 有人可以解释一下这是什么结构吗？

Question

我有以下ASM代码(OllyDbg),它应该包含用c开发的结构.有人能告诉我结构在c编程语言中是怎么样的吗？也许稍微解释一下你如何弄清楚结构中存储的内容等等......

非常感谢你!

CPU Disasm
Address   Hex dump          Command                           Comments
6A27F058  /$  68 E9A6286A   PUSH 6A28A6E9                     ; Entry point
6A27F05D  |.  64:FF35 00000 PUSH DWORD PTR FS:[0]
6A27F064  |.  8B4424 10     MOV EAX,DWORD PTR SS:[ESP+10]
6A27F068  |.  896C24 10     MOV DWORD PTR SS:[ESP+10],EBP
6A27F06C  |.  8D6C24 10     LEA EBP,[ESP+10]
6A27F070  |.  2BE0          SUB ESP,EAX
6A27F072  |.  53            PUSH EBX
6A27F073  |.  56            PUSH ESI
6A27F074  |.  57            PUSH EDI
6A27F075  |.  A1 E067336A   MOV EAX,DWORD PTR DS:[6A3367E0]
6A27F07A  |.  3145 FC       XOR DWORD PTR SS:[EBP-4],EAX
6A27F07D  |.  33C5          XOR EAX,EBP
6A27F07F  |.  50            PUSH EAX
6A27F080  |.  8965 E8       MOV DWORD PTR SS:[EBP-18],ESP
6A27F083  |.  FF75 F8       PUSH DWORD PTR SS:[EBP-8]
6A27F086  |.  8B45 FC       MOV EAX,DWORD PTR SS:[EBP-4]
6A27F089  |.  C745 FC FEFFF MOV DWORD PTR SS:[EBP-4],-2
6A27F090  |.  8945 F8       MOV DWORD PTR SS:[EBP-8],EAX
6A27F093  |.  8D45 F0       LEA EAX,[EBP-10]
6A27F096  |.  64:A3 0000000 MOV DWORD PTR FS:[0],EAX
6A27F09C  \.  C3            RETN

Answer 1

这是一个函数__SEH_prolog4,它是用于设置每个函数异常处理程序的编译器帮助程序.这是库中的列表(RunTmChk.lib/sehprolg4.obj):

.text:00000000                   __SEH_prolog4   proc near
.text:00000000
.text:00000000                   arg_4           = dword ptr  8
.text:00000000
.text:00000000 68 60 00 00 00      push    offset __except_handler4
.text:00000005 64 FF 35 00 00 00+  push    large dword ptr fs:0
.text:0000000C 8B 44 24 10         mov     eax, [esp+8+arg_4]
.text:00000010 89 6C 24 10         mov     [esp+8+arg_4], ebp
.text:00000014 8D 6C 24 10         lea     ebp, [esp+8+arg_4]
.text:00000018 2B E0               sub     esp, eax
.text:0000001A 53                  push    ebx
.text:0000001B 56                  push    esi
.text:0000001C 57                  push    edi
.text:0000001D A1 64 00 00 00      mov     eax, ds:___security_cookie
.text:00000022 31 45 FC            xor     [ebp-4], eax
.text:00000025 33 C5               xor     eax, ebp
.text:00000027 50                  push    eax
.text:00000028 89 65 E8            mov     [ebp-18h], esp
.text:0000002B FF 75 F8            push    dword ptr [ebp-8]
.text:0000002E 8B 45 FC            mov     eax, [ebp-4]
.text:00000031 C7 45 FC FE FF FF+  mov     dword ptr [ebp-4], 0FFFFFFFEh
.text:00000038 89 45 F8            mov     [ebp-8], eax
.text:0000003B 8D 45 F0            lea     eax, [ebp-10h]
.text:0000003E 64 A3 00 00 00 00   mov     large fs:0, eax
.text:00000044 C3                  retn
.text:00000044                   __SEH_prolog4   endp

有关详细信息,请参见此处

这不是程序员编写的代码,你看错了地方.