我想用我的Yesod应用程序实现大文件上传.现在我有:
module Handler.File where
import Import
import System.Random
import System.FilePath
import Control.Monad
import qualified Data.ByteString.Lazy as LBS
import qualified Data.Text.Encoding
-- upload
uploadDirectory :: FilePath -- FIXME: make this configurable
uploadDirectory = "incoming"
randomFileName :: IO FilePath
randomFileName = do
fname'base <- replicateM 20 (randomRIO ('a','z'))
let fname = uploadDirectory </> fname'base <.> "bin"
return fname
fileUploadForm :: Form (FileInfo, Textarea)
fileUploadForm = renderDivs $ (,)
<$> fileAFormReq "Choose a file"
<*> areq textareaField "What's on the file?" Nothing
getFileNewR :: Handler RepHtml
getFileNewR = do
(formWidget, formEnctype) <- generateFormPost fileUploadForm
defaultLayout $ do
setTitle "Upload new file."
$(widgetFile "file-new")
postFileNewR :: Handler RepHtml
postFileNewR = do
user <- requireAuth
((result, formWidget), formEnctype) <- runFormPost fileUploadForm
case result of
FormSuccess (fi,info) -> do
fn <- liftIO randomFileName
liftIO (LBS.writeFile fn (fileContent fi))
let newFile = File (entityKey user) fn info (fileName fi) (fileContentType fi)
fid <- runDB $ insert newFile
redirect (FileViewR fid)
_ -> return ()
defaultLayout $ do
setTitle "Upload new file."
$(widgetFile "file-new")
Run Code Online (Sandbox Code Playgroud)
它很好,除了几个问题:
文件的最大大小约为2兆字节.我有一个修复,但这是正确的方法吗?我的修复是覆盖我的应用程序的Yesod实例中的maximumContentLength方法的默认实现,如下所示:
maximumContentLength _(Just(FileNewR _))= 2*1024*1024*1024 - 2千兆字节maximumContentLength _ _ = 2*1024*1024 - 2兆字节
使用的内存量等于文件的大小.这真的不是最理想的.我想使用来自http://hackage.haskell.org/packages/archive/wai-extra/1.2.0.4/doc/html/Network-Wai-Parse.html的 tempFileBackEnd,但我不知道如何实际连线进入我的请求并使其与表单逻辑(隐藏_token字段等)一起使用.
上传是"一次性":如何使其适用于向用户显示进度的基于Flash/Html5的上传者的任何示例?