Mik*_*sen 16 sql oracle join oracle11g
在调试某些Oracle代码时,我遇到了这个查询:
SELECT TPM_TASK.TASKID FROM TPM_GROUP
INNER JOIN TPM_USERGROUPS ON TPM_GROUP.GROUPID = TPM_USERGROUPS.GROUPID
INNER JOIN TPM_TASK
INNER JOIN TPM_GROUPTASKS ON TPM_TASK.TASKID = TPM_GROUPTASKS.TASKID
INNER JOIN TPM_PROJECTVERSION ON TPM_TASK.PROJECTID = TPM_PROJECTVERSION.PROJECTID AND TPM_TASK.VERSIONID = TPM_PROJECTVERSION.VERSIONID
INNER JOIN TPM_TASKSTAGE ON TPM_TASK.STAGEID = TPM_TASKSTAGE.STAGEID
INNER JOIN TPM_PROJECTSTAGE ON TPM_PROJECTVERSION.STAGEID = TPM_PROJECTSTAGE.STAGEID
ON TPM_GROUP.GROUPID = TPM_GROUPTASKS.GROUPID
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我对这条线感到困惑:
INNER JOIN TPM_TASK
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我以前没见过JOIN没有ON条款的人.线路也令人困惑:
ON TPM_GROUP.GROUPID = TPM_GROUPTASKS.GROUPID
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这似乎是一个ON没有任何匹配的随机子句JOIN.查询运行时没有任何错误,并返回一堆数据,因此显而易见的是语法完全有效.有人能否详细了解这里究竟发生了什么?
Jus*_*ave 21
小宇宙......昨天我遇到了一个生成这种语法的工具,而且相当混乱.
显然,
FROM a
INNER JOIN b
INNER JOIN c ON (b.id = c.id)
ON (a.id = c.id)
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等效于嵌套子查询
FROM a
INNER JOIN (SELECT <<list of columns>>
FROM b
INNER JOIN c ON (b.id=c.id)) c
ON (a.id = c.id)
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我认为这只是排序查询的问题(因为只有INNER JOINs,它们的顺序并不那么重要).我重新调整了你的查询,现在它看起来像这样:
SELECT TPM_TASK.TASKID
FROM TPM_GROUP
INNER JOIN TPM_USERGROUPS
ON TPM_GROUP.GROUPID = TPM_USERGROUPS.GROUPID
INNER JOIN TPM_GROUPTASKS
ON TPM_GROUP.GROUPID = TPM_GROUPTASKS.GROUPID
INNER JOIN TPM_TASK
ON TPM_TASK.TASKID = TPM_GROUPTASKS.TASKID
INNER JOIN TPM_PROJECTVERSION
ON TPM_TASK.PROJECTID = TPM_PROJECTVERSION.PROJECTID
AND TPM_TASK.VERSIONID = TPM_PROJECTVERSION.VERSIONID
INNER JOIN TPM_TASKSTAGE
ON TPM_TASK.STAGEID = TPM_TASKSTAGE.STAGEID
INNER JOIN TPM_PROJECTSTAGE
ON TPM_PROJECTVERSION.STAGEID = TPM_PROJECTSTAGE.STAGEID
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你现在对它更有意义吗?它对我有用.
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