如何计算Objective-C字符串(NSString)中的行数?

fre*_*ara 26 cocoa enumeration newline objective-c

我想在Objective-C中计算NSString中的行数.

  NSInteger lineNum = 0;
  NSString *string = @"abcde\nfghijk\nlmnopq\nrstu";
  NSInteger length = [string length];
  NSRange range = NSMakeRange(0, length);
  while (range.location < length) {
      range = [string lineRangeForRange:NSMakeRange(range.location, 0)];
      range.location = NSMaxRange(range);
      lineNum += 1;
  }
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有没有更简单的方法?

Lod*_*oda 44

Apple建议使用此方法:

NSString *string;
unsigned numberOfLines, index, stringLength = [string length];

for (index = 0, numberOfLines = 0; index < stringLength; numberOfLines++)
    index = NSMaxRange([string lineRangeForRange:NSMakeRange(index, 0)]);
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文章.他们还解释了如何计算包装文本的行数.

  • 在现代代码中,应该使用NSUInteger. (12认同)

cob*_*bal 36

好吧,一个不是很有效但很好看(ish)的方式

NSString *string = @"abcde\nfghijk\nlmnopq\nrstu";
NSInteger length = [[string componentsSeparatedByCharactersInSet:
                                [NSCharacterSet newlineCharacterSet]] count];
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斯威夫特4:

myString.components(separatedBy: .newlines)
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  • 请记住,如果字符串很长,这将比你在问题中发布的代码效率低很多*,因为它会为每一行创建一个新的字符串对象.确保您了解在执行此操作时性能的重要性,以及字符串大小的上限. (4认同)

joh*_*les 5

如果你想考虑文本的宽度,你可以用 TextKit (iOS7+) 做到这一点:

func numberOfLinesForString(string: String, size: CGSize, font: UIFont) -> Int {
    let textStorage = NSTextStorage(string: string, attributes: [NSFontAttributeName: font])

    let textContainer = NSTextContainer(size: size)
    textContainer.lineBreakMode = .ByWordWrapping
    textContainer.maximumNumberOfLines = 0
    textContainer.lineFragmentPadding = 0

    let layoutManager = NSLayoutManager()
    layoutManager.textStorage = textStorage
    layoutManager.addTextContainer(textContainer)

    var numberOfLines = 0
    var index = 0
    var lineRange : NSRange = NSMakeRange(0, 0)
    for (; index < layoutManager.numberOfGlyphs; numberOfLines++) {
        layoutManager.lineFragmentRectForGlyphAtIndex(index, effectiveRange: &lineRange)
        index = NSMaxRange(lineRange)
    }

    return numberOfLines
}
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