当满足两个条件时,jquery执行函数

Question

我需要mvFinishItUp()在满足两个条件时执行特定的功能.更具体地说,一个条件是另一个条件的回调成功$.ajax是代码的正常流程,直到它到达函数.有点这样:

$.ajax({
    url: mv_finalUrl,
    success: function (data) {
        mvFinishItUp(data);
    },
    dataType: 'html'
});

/* here a lot more code, with animations and some delays */

mvFinishItUp(data) {
    /* My function code */
    /* But this code must only run after it has been called via the call back
       and after all the other code has been ran as well */
}

因此,如果ajax回调更快,或者相反,函数必须等待所有代码.有关如何实施这一点的任何想法？

我愿意改变脚本代码的整个概念,因为我相信ajax和函数本身之间的松散代码应该转到函数中...

Answer 1

这是jQuery Deferred对象的完美用例.

success:从AJAX调用中删除参数,稍后注册处理程序:

var jqxhr = $.ajax(...); 

// do some other synchronous stuff
...

// and *then* register the callback
jqxhr.done(mvFinishItUp);

延迟对象在该事件已经完成后在AJAX事件上注册时(通过设计)非常好地应对.