Access 2010:查询表达式中的语法错误(缺少运算符)

zin*_*non 11 sql ms-access-2010

我希望在我的SQL查询中有三个表,但是我收到一条错误消息.

我有这个sql代码:

 SELECT warehouse.expiry_date, pharmacy.expiry_date, drugs.active_substance, 
 drugs.strength, drugs.strength_type, drugs.dosage_form, drugs.minimum_quantity, 
 SUM(warehouse.in_quant)+SUM(pharmacy.in_quant)-SUM(warehouse.out_quant)-
 SUM(pharmacy.out_quant) AS Total_available_stock

 FROM drugs as a 
  INNER JOIN warehouse as b
    ON a.ID = b.drug_id 
  INNER JOIN pharmacy as c 
    ON b.drug_id = c.drug_id
 GROUP BY warehouse.expiry_date, pharmacy.expiry_date, drugs.active_substance, 
 drugs.strength, drugs.strength_type, drugs.dosage_form, drugs.minimum_quantity;
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我得到错误:

 Syntax error (missing operator) in query expression in 'a.ID = b.drug_id 
 INNER JOIN pharmacy as c
     on b.drug_id = c.drug_i'.
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有什么帮助吗?

Guf*_*ffa 43

在Access中,如果有多个联接,则需要使用括号:

FROM (drugs as a 
  INNER JOIN warehouse as b
    ON a.ID = b.drug_id) 
  INNER JOIN pharmacy as c 
    ON b.drug_id = c.drug_id
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  • 谢谢.无意义的parantheses,另一个看不起Access的原因. (8认同)
  • 啊。荒谬的。桑克斯。 (2认同)

Jos*_* U. 5

只是想补充一点,当您有 2 个以上的内部联接时,它会变得更加混乱。然后您需要在每个内部连接的开头和结尾添加一个额外的括号(最后一个除外)

例子:

 FROM ((drugs as a 
  INNER JOIN warehouse as b
    ON a.ID = b.drug_id) 
  INNER JOIN pharmacy as c1 
    ON b.drug_id1 = c1.drug_id)
  INNER JOIN pharmacy as c2 
    ON b.drug_id2 = c2.drug_id
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