Employee Table:
Empid FNAme LName Hair Race
1 john adam 1 1
2 clift susanne 2 3
Code Table:
code type description
1 hair black
2 hair brown
1 race black
3 race white
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我们需要将输出数据作为empid, Fname, Lname, Hair, Race; 其中hair和race不显示为代码,但描述形成代码表.
我是初学sql.Can你请帮助写一个查询我没有得到每个下面的查询预期的输出
select E.Empid,E.FName,E.Lname,c.description as Hair,c.description as race
From Employee2 E inner join code c
on (c.code = E.Hair )
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你应该加入你的代码表两次:
SQL语句
SELECT E.EmpID
, E.FName
, E.LName
, c1.Description AS Hair
, c2.Description AS Race
FROM Employee E
INNER JOIN Code c1 ON c1.Code = e.Hair AND c1.type = 'hair'
INNER JOIN Code c2 ON c2.Code = e.Race AND c2.type = 'race'
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请注意,如果其中任何一个都可以NULL,您可能希望更改INNER JOIN为LEFT OUTER JOIN
说,我建议你为Hair和Race创建一个单独的代码表.
尝试将所有内容转储到一个代码表中只会让人感到困惑,并迫使您最多编写次优查询.您强制自己将类型添加到代码表以及您将创建的每个联接.
一个更好的选择是
Employee Table:
Empid FNAme LName Hair Race
1 john adam 1 1
2 clift susanne 2 3
HairCode Table:
code description
1 black
2 brown
RaceCode Table:
1 black
3 white
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并简化你的陈述
SELECT E.EmpID
, E.FName
, E.LName
, c1.Description AS Hair
, c2.Description AS Race
FROM Employee E
INNER JOIN HairCode c1 ON c1.Code = e.Hair
INNER JOIN RaceCode c2 ON c2.Code = e.Race
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您将获得更好的性能和更小的足迹免费.
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