jQuery - 等到SlideUp结束()

Question

在继续编写脚本之前,我怎么能等到jQuery函数slideUp()结束？

<script type="text/javascript">
$(document).ready(function() {
    $("div[class=item]").click(function() {
        var id = $(this).attr("id");
        $("#content").slideUp();
        switch(id) {
            // Applications
            case "rampro":
                $("#content").css("text-align", "left");
                $("#content").load("inc/pages/rampro.html");
                $("#content").slideDown();
                break
            case "diskman":
                $("#content").css("text-align", "left");
                $("#content").load("inc/pages/diskman.html");
                break
            case "iconmap":
                $("#content").css("text-align", "left");
                $("#content").load("inc/pages/iconmap.html");
                break
            // Websites
            case "benoks":
                $("#content").css("text-align", "left");
                $("#content").load("inc/pages/benoks.html");
                break
            case "linkbase":
                $("#content").css("text-align", "left");
                $("#content").load("inc/pages/linkbase.html");
                break
            case "jamesbrooks":
                $("#content").css("text-align", "left");
                $("#content").load("inc/pages/jamesbrooks.html");
                break
            default:
                $("#content").css("text-align","center");
                $("#content").html("<h1>something went wrong, try again!</h1>");
        }
        return false;
    });
});

Answer 1

使用回调机制并让代码在回调中运行.

$('#something').slideUp('fast', function() {
   ... stuff to do after the slide is complete...
});