Rao*_*oot 1 sql ruby-on-rails ruby-on-rails-3
我开始注意到终端我的Rails应用程序产生了太多的SQL语句,其中许多都不是必需的.我确实记得在某个地方阅读这可能是一个问题而且现在随着我的数据增长它显着减慢了应用程序的速度.
例如,我有包含曲目的版本.艺术家可以分配到曲目和发行.当我加载一个只有8个轨道的版本时,它似乎正在运行DB中的每个轨道来找到这些关系!?!
例如,请参见下文,这是一个非常小的示例,但这些轨道实际上都与该版本无关.它正在经历数据库中的每个轨道!
任何一般指针?
Artist Load (0.6ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 12
Artist Load (0.6ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 19
Artist Load (0.6ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 21
Artist Load (0.9ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 22
Artist Load (0.7ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 23
Artist Load (0.6ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 24
Artist Load (0.9ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 25
Artist Load (1.0ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 26
Artist Load (0.6ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 27
Artist Load (0.9ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 28
Artist Load (0.6ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 29
Artist Load (0.6ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 30
Artist Load (0.6ms) SELECT `artists`.* FROM `artists` INNER JOIN `artists_tracks` ON `artists`.`id` = `artists_tracks`.`artist_id` WHERE `artists_tracks`.`track_id` = 31
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这是涉及的模型:
class Artist < ActiveRecord::Base
has_many :artist_releases
has_many :releases, :through => :artist_releases
has_many :artists_tracks
has_many :tracks, :through => :artists_tracks
end
class ArtistRelease < ActiveRecord::Base
belongs_to :artist
belongs_to :release
end
class ArtistsTrack < ActiveRecord::Base
belongs_to :artist
belongs_to :release
belongs_to :track
end
class Release < ActiveRecord::Base
has_many :artist_releases
has_many :artists, :through => :artist_releases
accepts_nested_attributes_for :artists, :reject_if => lambda { |a| a[:name].blank? }
accepts_nested_attributes_for :artist_releases
has_many :releases_tracks, :dependent => :destroy
has_many :tracks, :through => :releases_tracks, :order => "releases_tracks.position"
accepts_nested_attributes_for :tracks, :reject_if => lambda { |a| a[:name].blank? }, :allow_destroy => :true
accepts_nested_attributes_for :releases_tracks
end
class ReleasesTrack < ActiveRecord::Base
default_scope :order => 'releases_tracks.position ASC'
acts_as_list :scope => :release_id
belongs_to :release
belongs_to :track
end
class Track < ActiveRecord::Base
has_many :releases_tracks, :dependent => :destroy
has_many :releases, :through => :releases_tracks
has_many :artists_tracks
has_many :artists, :through => :artists_tracks
accepts_nested_attributes_for :artists, :reject_if => lambda { |a| a[:name].blank? }
accepts_nested_attributes_for :artists_tracks
end
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从Rails生成的查询中,看起来你正在做这样的事情,当你引用它时,它会单独加载每个艺术家:
release.tracks.each{ |t| t.artist }
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您应该热切地加载艺术家,以便在单个查询中预先加载它们:
release.tracks.includes(:artist).each{ |t| t.artist }
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该includes方法非常灵活,允许您急切地加载多个关联,甚至嵌套关联:
Release.first.includes(:releases_tracks => {:track => :artist})
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这将加载第一个Release,然后是所有的ReleaseTracks,然后是所有的Tracks,以及仅4个查询中的所有Tracks'Artists(每个表1个).这比单独加载每条记录更有效.
"Active Record查询"界面指南中的"预先加载关联 "一节中提供了更多信息.
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