ggplot2保持未使用的级别barplot

Ulr*_*rik 72 r legend levels ggplot2

我想在我的条形图中绘制未使用的级别(即,计数为0的级别),但是,未使用的级别被删除,我无法弄清楚如何保留它们

df <- data.frame(type=c("A", "A", "A", "B", "B"), group=rep("group1", 5))
df$type <- factor(df$type, levels=c("A","B", "C"))

ggplot(df, aes(x=group, fill=type)) + geom_bar()
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在上面的例子中,我想看到C计数为0,但它完全没有...

感谢Ulrik的帮助

编辑:

这就是我想要的

df <- data.frame(type=c("A", "A", "A", "B", "B"), group=rep("group1", 5))
df1 <- data.frame(type=c("A", "A", "A", "B", "B", "A", "A", "C", "B", "B"), group=c(rep("group1", 5),rep("group2", 5)))

df$type <- factor(df$type, levels=c("A","B", "C"))
df1$type <- factor(df1$type, levels=c("A","B", "C"))
df <- data.frame(table(df))

df1 <- data.frame(table(df1))

ggplot(df, aes(x=group, y=Freq, fill=type)) + geom_bar(position="dodge")
ggplot(df1, aes(x=group, y=Freq, fill=type)) + geom_bar(position="dodge")
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猜测解决方案是使用table()计算频率然后绘图

smi*_*lig 60

这样做你想要的吗?

ggplot(df, aes(x=type)) + geom_bar() + scale_x_discrete(drop=FALSE)
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在此输入图像描述


Jar*_*nha 39

您需要在两个比例(fill和x)上设置drop = FALSE,如下所示:

library(ggplot2)
df <- data.frame(type=c("A", "A", "A", "B", "B"), group=rep("group1", 5))
df1 <- data.frame(type=c("A", "A", "A", "B", "B", "A", "A", "C", "B", "B"), group=c(rep("group1", 5),rep("group2", 5)))
df$type <- factor(df$type, levels=c("A","B", "C"))
df1$type <- factor(df1$type, levels=c("A","B", "C"))

plt <- ggplot(df, aes(x=type, fill=type)) + geom_bar(position='dodge') + scale_fill_discrete(drop=FALSE) + scale_x_discrete(drop=FALSE)
plt1 <-  ggplot(df1, aes(x=type, fill=type)) + geom_bar(position='dodge') + scale_fill_discrete(drop=FALSE) + scale_x_discrete(drop=FALSE)
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编辑:

我很确定这很有效.忘了将x更改为type而不是group并且position ='dodge'!只需粘贴并测试即可.stat_bin处理零计数的bin.检查文档.


Ulr*_*rik 9

降低水平不起作用.在第一个示例中删除级别

library(ggplot2)

df <- data.frame(type=c("A", "A", "A", "B", "B"), group=rep("group1", 5))
df$type <- factor(df$type, levels=c("A","B", "C"))

ggplot(df, aes(x=group, fill=type)) + geom_bar(position="dodge") + scale_x_discrete(drop=FALSE) + scale_fill_discrete(drop=FALSE)
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结果在这个情节:

在此输入图像描述

解决方案是第二个示例,其中手动计算频率:

df <- data.frame(type=c("A", "A", "A", "B", "B"), group=rep("group1", 5))
df1 <- data.frame(type=c("A", "A", "A", "B", "B", "A", "A", "C", "B", "B"), group=c(rep("group1", 5),rep("group2", 5)))

df$type <- factor(df$type, levels=c("A","B", "C"))
df1$type <- factor(df1$type, levels=c("A","B", "C"))

df <- data.frame(table(df))
df1 <- data.frame(table(df1))

df$plot = "A"
df1$plot = "B"

df <- rbind(df, df1)

ggplot(df, aes(x=group, y=Freq, fill=type)) + geom_bar(position="dodge", stat="identity") + facet_wrap( ~ plot, scales="free")
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结果如下:

在此输入图像描述

最后一个是信息量最大的,因为空间被count = 0的类别占用