我有一个多维数组:
array (
array (
"username" => "foo",
"favoriteGame" => "Mario"
)
array (
"username" => "bar",
"favoriteGame" => "Mario"
)
array (
"username" => "xyz",
"favoriteGame" => "Zelda"
)
)
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我怎样才能以最简单的方式获得喜欢玩马里奥的人的用户名?
编辑: 我的错:忘记明确提到"favoriteGame"值是动态的,我不知道它是提前的.
我的解决方案
foreach($users as $key => $value)
{
if(!isset($$value['favoriteGame']))
{
$$value['favoriteGame'] = array();
}
array_push($$value['favoriteGame'], $value['username']);
}
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迭代每个子数组并找到它的favoriteGame值.如果还没有数组$ favoriteGame创建它.将实际子数组的username-value推送到$ favoriteGame数组.
感谢您的回复,我无法正确地回答这个问题.
function getUsernamesByFavoriteGame($data, $game) {
$usernames = array();
foreach($data as $arr) {
if ($arr['favoriteGame'] == $game) {
$usernames[] = $arr['username'];
}
}
return $usernames;
}
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$usernames = array();
foreach($array as $key => $value) {
if ($value['favoriteGame'] == 'Mario') {
$usernames[] = $value['username'];
}
}
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