在javascript中将Date()舍入到最近的5分钟

Question

使用一个Date()实例,我怎样才能将时间缩短到最接近的五分钟？

例如:如果是下午4:47,它会将时间设置为下午4:45

Answer 1

如果你已经有了一个Date对象,这很简单:

var coeff = 1000 * 60 * 5;
var date = new Date();  //or use any other date
var rounded = new Date(Math.round(date.getTime() / coeff) * coeff)

Answer 2

使用 ES6 和部分函数，​​它可以很优雅。选择是否需要四舍五入到最接近或始终向下/向上：

const roundTo = roundTo => x => Math.round(x / roundTo) * roundTo;    
const roundDownTo = roundTo => x => Math.floor(x / roundTo) * roundTo;
const roundUpTo = roundTo => x => Math.ceil(x / roundTo) * roundTo;

const roundTo5Minutes = roundTo(1000 * 60 * 5);
const roundDownTo5Minutes = roundDownTo(1000 * 60 * 5);
const roundUpTo5Minutes = roundUpTo(1000 * 60 * 5);

const now = new Date();
const msRound = roundTo5Minutes(now)
const msDown = roundDownTo5Minutes(now)
const msUp = roundUpTo5Minutes(now)

console.log(now);
console.log(new Date(msRound));
console.log(new Date(msDown));
console.log(new Date(msUp));

Answer 3

我知道现在回答有点晚了，但也许它可以帮助别人。如果您按照以下方式进行会议记录

new Date().getMinutes()

您可以在最后 5 分钟内

new Date().getMinutes() - (new Date().getMinutes()%5)

Answer 4

四舍五入到最接近的x分钟

这是一种将日期对象四舍五入到最接近的x分钟的方法，或者，如果您不提供任何日期，则它将舍入当前时间。

let getRoundedDate = (minutes, d=new Date()) => {

  let ms = 1000 * 60 * minutes; // convert minutes to ms
  let roundedDate = new Date(Math.round(d.getTime() / ms) * ms);

  return roundedDate
}


// USAGE //

// Round existing date to 5 minutes
getRoundedDate(5, new Date()); // 2018-01-26T00:45:00.000Z

// Get current time rounded to 30 minutes
getRoundedDate(30); // 2018-01-26T00:30:00.000Z

Answer 5

Date-fns现在有一个函数可以对日期的分钟进行四舍五入。请参阅https://date-fns.org/v2.21.3/docs/roundToNearestMinutes

const roundToNearestMinutes = require('date-fns/roundToNearestMinutes')
// OR: import roundToNearestMinutes from 'date-fns/roundToNearestMinutes'
console.log(roundToNearestMinutes(new Date(), {nearestTo: 5}));
// e.g. 2021-05-19T22:45:00.000Z