我有一张桌子,假设它有四列
Id, Name, Cell_no, Cat_id。我需要返回计数Cat_id大于 的所有列1。
该组应在Cell_no和上完成Name。到目前为止我做了什么..
select Cell_no, COUNT(Cat_id)
from TableName
group by Cell_Number
having COUNT(Cat_id) > 1
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但我需要的是这样的东西。
select *
from TableName
group by Cell_Number
having COUNT(Cat_id) > 1
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Pratik 的答案很好,但IN您需要JOIN像这样返回结果集,而不是使用运算符(仅适用于单个值)
SELECT t.*
FROM tableName t
INNER JOIN
(SELECT Cell_no, Name
FROM TableName
GROUP BY Cell_no , Name
HAVING COUNT(Cat_id) > 1) filter
ON t.Cell_no = filter.Cell_no AND t.Name = filter.Name
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