Openssl和PHP

Question

我试图用PHP加载openssl cli工具生成的私钥.我使用了以下命令和PHP代码:

openssl genrsa -des3 4096 -out private.key

if (!($key = openssl_pkey_get_private("file://private.key", "password")));
{
      return false;
}

我确定密码是正确的,文件也是PEM格式,但它一直返回false.我究竟做错了什么？

谢谢,Jori.

Answer 1

请注意,file://path/to/file.pem在文档中表示文件协议+文件路径.在像OS这样的UNIX中,就是这样的file:///rsa_private_key.pem.路径字符串中有三个斜杠,而不是TWO.并且file://不能省略.

Answer 2

将密钥放入 var 中要容易得多：

$public = "-----BEGIN PUBLIC KEY-----
MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQDfmlc2EgrdhvakQApmLCDOgP0n
NERInBheMh7J/r5aU8PUAIpGXET/8+kOGI1dSYjoux80AuHvkWp1EeHfMwC/SZ9t
6rF4sYqV5Lj9t32ELbh2VNbE/7QEVZnXRi5GdhozBZtS1gJHM2/Q+iToyh5dfTaA
U8bTnLEPMNC1h3qcUQIDAQAB
-----END PUBLIC KEY-----";

$private = "-----BEGIN RSA PRIVATE KEY-----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-----END RSA PRIVATE KEY-----";

if (!$privateKey = openssl_pkey_get_private($private)) die('Loading Private Key failed');
if (!$publicKey = openssl_pkey_get_public($public)) die('Loading Public Key failed');

我还将包括一个小的编码/解码示例：

$encrypted = '';
$decrypted = '';

$plaintext = 'This is just some text to encrypt';

echo '<p>$plaintext = ' . $plaintext . '<p>';

if (!openssl_public_encrypt($plaintext, $encrypted, $publicKey))    die('Failed to encrypt data');

echo '<p>$encrypted = ' . $encrypted . '<p>';

if (!openssl_private_decrypt($encrypted, $decrypted, $privateKey))  die('Failed to decrypt data');

echo '<p>$decrypted = ' . $decrypted . '<p>';

或者以防万一您可以使用 php 生成密钥：

$NEW_KEY = openssl_pkey_new(array(
    'private_key_bits' => 1024,
    'private_key_type' => OPENSSL_KEYTYPE_RSA,
        ));

openssl_pkey_export_to_file($NEW_KEY, 'private.key');

$NEW_KEY_DETAILS = openssl_pkey_get_details($NEW_KEY);
file_put_contents('public.key', $NEW_KEY_DETAILS['key']);

openssl_free_key($NEW_KEY);