urllib.urlopen无法正常工作.有解决方法吗？

Question

我得到一个getaddress错误,在做了一些调查后,看起来它可能是我的企业内部网不允许连接(我假设由于安全性,虽然IE工作很奇怪但不允许Python打开一个网址).有没有一种安全的方法来解决这个问题？

这是确切的错误:

Traceback (most recent call last):
  File "<pyshell#1>", line 1, in <module>
    b = urllib.urlopen('http://www.google.com')
  File "C:\Python26\lib\urllib.py", line 87, in urlopen
    return opener.open(url)
  File "C:\Python26\lib\urllib.py", line 203, in open
    return getattr(self, name)(url)
  File "C:\Python26\lib\urllib.py", line 342, in open_http
    h.endheaders()
  File "C:\Python26\lib\httplib.py", line 868, in endheaders
    self._send_output()
  File "C:\Python26\lib\httplib.py", line 740, in _send_output
    self.send(msg)
  File "C:\Python26\lib\httplib.py", line 699, in send
    self.connect()
  File "C:\Python26\lib\httplib.py", line 683, in connect
    self.timeout)
  File "C:\Python26\lib\socket.py", line 498, in create_connection
    for res in getaddrinfo(host, port, 0, SOCK_STREAM):
IOError: [Errno socket error] [Errno 11001] getaddrinfo failed

更多信息:我也用urllib2.urlopen得到了这个错误

Answer 1

您可能需要填写代理信息.

import urllib2
proxy_handler = urllib2.ProxyHandler({'http': 'http://yourcorporateproxy:12345/'})
proxy_auth_handler = urllib2.HTTPBasicAuthHandler()
proxy_auth_handler.add_password('realm', 'host', 'username', 'password')

opener = urllib2.build_opener(proxy_handler, proxy_auth_handler)
opener.open('http://www.stackoverflow.com')