在android中使用WCF服务

Ore*_*n A 4 wcf android

我创建了这项服务(使用WCF,Azure):

[ServiceBehavior(AddressFilterMode = AddressFilterMode.Any)]
public class Service1 : IPMPService
{
    public int Dummy()
    {
        return 0;
    }
}
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IPMPService在哪里:

[ServiceContract]
public interface IPMPService
{
    [WebGet()]
    [OperationContract]
    int Dummy();
}
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并尝试在我的Android应用程序中使用它:
第一次尝试:

String METHOD_NAME = "DummyRequest";
String NAMESPACE = "http://tempuri.org/";
String URL = "http://tyty.cloudapp.net/Service1.svc";
String SOAP_ACTION = "http://tyty.cloudapp.net/Service1.svc/Dummy";

String res = "";
try {
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
    androidHttpTransport.call(SOAP_ACTION, envelope);
    SoapPrimitive result = (SoapPrimitive) envelope.getResponse();
    // to get the data
    String resultData = result.toString();
    res = resultData;
    // 0 is the first object of data
    } catch (Exception e) {
        res = e.getMessage();
    }   
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结果:SoapFault - faultcode:'a:ActionNotSupported'faultstring:'由于EndpointDispatcher上的ContractFilter不匹配,无法在接收方处理带有Action的消息'http://tyty.cloudapp.net/Service1.svc/Dummy' .这可能是由于合同不匹配(发送方与接收方之间的操作不匹配)或发送方与接收方之间的绑定/安全性不匹配.检查发送方和接收方是否具有相同的合同和相同的绑定(包括安全要求,例如消息,传输,无).faultactor:'null'detail:null

第二次尝试(取自此处):

String SERVER_HOST = "http://tyty.cloudapp.net";
int SERVER_PORT = 8080;
String URL1 = "/Service1.svc/Dummy";
String keywords = null;
HttpEntity entity = null;
HttpClient client = new DefaultHttpClient();
HttpGet get = new HttpGet(URL1);
try {
HttpResponse response = client.execute(target, get);
entity = response.getEntity();
keywords = EntityUtils.toString(entity);
} catch (Exception e) {
e.printStackTrace();
   } finally {
if (entity != null)
        try {
        entity.consumeContent();
    } catch (IOException e) {
  }
}  
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结果:java.net.UnknownHostException:无法解析主机"http://tyty.cloudapp.net":没有与主机名关联的地址

我还在c#中创建了一个(工作)客户端,这是它的App.config:

<configuration>
  <system.serviceModel>
    <bindings>
      <basicHttpBinding>
        <binding name="BasicHttpBinding_IPMPService" closeTimeout="00:01:00"
            openTimeout="00:01:00" receiveTimeout="00:10:00" sendTimeout="00:01:00"
            allowCookies="false" bypassProxyOnLocal="false" hostNameComparisonMode="StrongWildcard"
            maxBufferSize="65536" maxBufferPoolSize="524288" maxReceivedMessageSize="65536"
            messageEncoding="Text" textEncoding="utf-8" transferMode="Buffered"
            useDefaultWebProxy="true">
          <readerQuotas maxDepth="32" maxStringContentLength="8192" maxArrayLength="16384"
              maxBytesPerRead="4096" maxNameTableCharCount="16384" />
          <security mode="None">
            <transport clientCredentialType="None" proxyCredentialType="None"
                realm="" />
            <message clientCredentialType="UserName" algorithmSuite="Default" />
          </security>
        </binding>
      </basicHttpBinding>
    </bindings>
    <client>
      <endpoint address="http://tyty.cloudapp.net/Service1.svc"
          binding="basicHttpBinding" bindingConfiguration="BasicHttpBinding_IPMPService"
          contract="IPMPService" name="BasicHttpBinding_IPMPService" />
    </client>
  </system.serviceModel>
</configuration>
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如前所述,Android的两次尝试都失败了.任何人都可以告诉我我做错了什么,以及如何正确做到这一点?
谢谢.

Cod*_*odo 8

你的第一次尝试非常接近.只需要两个修复:

String METHOD_NAME = "Dummy";
String NAMESPACE = "http://tempuri.org/";
String URL = "http://tyty.cloudapp.net/Service1.svc";
String SOAP_ACTION = "http://tempuri.org/IPMPService/Dummy";

String res = "";
try {
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
    androidHttpTransport.call(SOAP_ACTION, envelope);
    SoapPrimitive result = (SoapPrimitive) envelope.getResponse();
    // to get the data
    String resultData = result.toString();
    res = resultData;
    // 0 is the first object of data
} catch (Exception e) {
    res = e.getMessage();
}   
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第一个是方法名称:它只是Dummy(而不是DummyRequest).第二个是SOAP动作:它是http://tempuri.org/IPMPService/Dummy.

两者都可以从WSDL派生.您的操作定义为:

<wsdl:operation name="Dummy">
    <wsdl:input wsaw:Action="http://tempuri.org/IPMPService/Dummy" message="tns:IPMPService_Dummy_InputMessage"/>
    <wsdl:output wsaw:Action="http://tempuri.org/IPMPService/DummyResponse" message="tns:IPMPService_Dummy_OutputMessage"/>
</wsdl:operation>
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然后,如果您查看IPMPService_Dummy_InputMessage消息类型,则调用该元素Dummy:

<wsdl:message name="IPMPService_Dummy_InputMessage">
    <wsdl:part name="parameters" element="tns:Dummy"/>
</wsdl:message>
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SOAP操作可在此处找到:

<wsdl:operation name="Dummy">
    <soap:operation soapAction="http://tempuri.org/IPMPService/Dummy" style="document"/>
    ...
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