在Go中使用大整数值？(ParseInt只转换为"2147483647"？)

Question

如何在Go中将一长串数字(50位)转换为整数？

我得到以下代码的输出:

number = 2147483647

err = strconv.ParseInt:解析"37107287533902102798797998220837590246510135740250":值超出范围

它似乎只能将数字转换为2147483647.

package main

import "fmt"
import "io/ioutil"
import "strings"
import "strconv"

var (
        number int64
)

func main() {
    fData,err := ioutil.ReadFile("one-hundred_50.txt")
    if err != nil {
            fmt.Println("Err is ",err)
        }   
    strbuffer := string(fData)
    lines := strings.Split(strbuffer, "\n")

    for i, line := range lines {
        fmt.Printf("%d: %s\n", i, line)
        number, err := strconv.Atoi(line)
        fmt.Println("number = ", number)
        fmt.Println("err = ", err)
    }   
}

Answer 1

你想要math/big包,它提供任意精度的整数支持.

import "math/big"

func main() {
    // ...
    for i, line := range lines {
        bi := big.NewInt(0)
        if _, ok := bi.SetString(line, 10); ok {
            fmt.Printf("number = %v\n", bi)
        } else {
            fmt.Printf("couldn't interpret line %#v\n", line)
        }
    }
}

这是一个很好的工作示例.