附加char数组以创建字符串

Question

如何添加所有charAcro []来创建字符串？示例charAcro [0] = a,charAcro [1] = b,charAcro [2] = c,这使得字符串abc

 while(resultSet.next()){
                    String Name = rs.getString(1);
                    String Acro=Name;
                    String delimiterAcro = " ";
                    String[] temp =null;
                    char[] charAcro = null;
                    temp = Name.split(delimiterAcro);
                    for(int i = 0;i<temp.length;++i){
                    charAcro[i] = temp[i].charAt(0);
                    //SOME CODE HERE?
                    }

      }

Answer 1

有一个String可用的构造函数,一个char数组,

char data[] = {'a', 'b', 'c'};
String str = new String(data);

我正在研究它,请研究Java命名约定.类名应该是名词,大小写混合,每个内部单词的首字母大写.变量是大小写混合的小写首字母.内部单词以大写字母开头.

例如,在您的代码段中,

String Name = rs.getString(1);

这不好,如果不是错的话.

而且,你可能在行上有一个NullPointerException,

charAcro[i] = temp[i].charAt(0);

因为你没有初始化数组.以下是应该适合您的代码.

String name = rs.getString(1);
String[] temp = name.split(" ");
char[] charAcro = new char[temp.length];
for (int i = 0; i < temp.length; ++i) {
    charAcro[i] = temp[i].charAt(0);
}
System.out.println(new String(charAcro));