C:通过引用传递struct

Question

我已经定义了以下结构:

typedef struct {
    double salary;
} Employee;

我想改变它的价值salary.我尝试通过引用传递它,但值保持不变.以下是代码:

void raiseSalary (Employee* e, double newSalary) {
    Employee myEmployee = *e;
    myEmployee.salary = newSalary;
}

当我调用此函数时,salary保持不变.我究竟做错了什么？

Answer 1

您正在传递指向原始的指针,但随后您创建了它的副本:

Employee myEmployee =*e;

创建一个副本.

e->salary = newSalary;

会做的.或者,如果您出于某种原因必须有一个辅助变量:

Employee* myEmployee =e;
Myemployee->salary= newSalary;

这样,两个变量都将指向同一个对象.