从代码中引用字符串资源

Question

我在strings.xml中声明了以下字符串:

<string name="last_msg">Your last click was on</string>

现在当有人点击按钮时,我希望textview显示带有空格的字符串,然后显示一个时间戳的变量值.

不幸的是,使用@ string/last_msg不起作用,我不知道如何正确地做到这一点所以我不是硬编码的内容.

这是我的onClick函数的代码:

public void showMsgNow(View view) {
    TextView lastMsg = (TextView)findViewById(R.id.textView2);
    long currentTimeStamp = System.currentTimeMillis();
    lastMsg.setText(@string/last_msg + " " + currentTimeStamp);
}

我是新手,任何帮助都会很棒!

Answer 1

我在Google上找到了答案:

getString(R.string.last_msg)

Answer 2

你不能String直接访问@,因为你需要有上下文资源然后只是这样做...

lastMsg.setText(context.getResources().getString(R.string.last_msg) + " " + currentTimeStamp);

在你的情况下使用

<string name="last_msg">Your last click was on %1$s</string>

执行:

public void showMsgNow(View view) {
    TextView lastMsg = (TextView)findViewById(R.id.textView2);
    long currentTimeStamp = System.currentTimeMillis();
    lastMsg.setText(context.getResources()
        .getString(R.string.last_msg, currentTimeStamp));
}

Answer 3

// getString is method of context
if (this instanceof Context) 
//If you are in Activity or Service class            
 lastMsg.setText(getString(R.string.last_msg)+ " " + currentTimeStamp);
else                         
//you need to context to get the string 
  lastMsg.setText(getString(mContext,R.string.last_msg)+ " " + currentTimeStamp);


  public String getString(Context mContext, int id){
     return mContext.getResources().getString(id);
  }