这里是新手R用户.所以我有一个数据集格式如下:
Date Temp Month
1-Jan-90 10.56 1
2-Jan-90 11.11 1
3-Jan-90 10.56 1
4-Jan-90 -1.67 1
5-Jan-90 0.56 1
6-Jan-90 10.56 1
7-Jan-90 12.78 1
8-Jan-90 -1.11 1
9-Jan-90 4.44 1
10-Jan-90 10.00 1
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在R语法中:
datacl <- structure(list(Date = structure(1:10, .Label = c("1990/01/01",
"1990/01/02", "1990/01/03", "1990/01/04", "1990/01/05", "1990/01/06",
"1990/01/07", "1990/01/08", "1990/01/09", "1990/01/10"), class = "factor"),
Temp = c(10.56, 11.11, 10.56, -1.67, 0.56, 10.56, 12.78,
-1.11, 4.44, 10), Month = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L)), .Names = c("Date", "Temp", "Month"), class = "data.frame", row.names = c(NA,
-10L))
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我想对特定月份的数据进行子集化,并将更改因子应用于临时值,然后保存结果.所以我有类似的东西
idx <- subset(datacl, Month == 1) # Index
results[idx[,2],1] = idx[,2]+change # change applied to only index values
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但我一直得到一个错误
Error in results[idx[, 2], 1] = idx[, 2] + change:
only 0's may be mixed with negative subscripts
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任何帮助,将不胜感激.
首先,给变化因子一个值:
change <- 1
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现在,以下是创建索引的方法:
# one approach to subsetting is to create a logical vector:
jan.idx <- datacl$Month == 1
# alternatively the which function returns numeric indices:
jan.idx2 <- which(datacl$Month == 1)
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如果您只想要一月份的数据子集,
jandata <- datacl[jan.idx,]
transformed.jandata <- transform(jandata, Temp = Temp + change)
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要保留整个数据框,但仅将变化因子添加到 Jan temps:
datacl$Temp[jan.idx] <- datacl$Temp[jan.idx] + change
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