adr*_*ian 9 android entity http
我这样做了:
response = httpclient.execute(targetHost, httppost);
if(response.getStatusLine().getStatusCode() == 200)
{
HttpEntity entity = response.getEntity();
System.out.println("Entity:"+entity);
if (entity != null)
{
String responseBody = EntityUtils.toString(entity);
System.out.println("finalResult"+responseBody.toString());
}
Run Code Online (Sandbox Code Playgroud)
关于它的事情是第一个println()
显示这个:org.apache.http.conn.BasicManagedEntity@481e8150
这是好的.
但第二个System.out.println("finalResult"+responseBody.toString());
只显示这个finalResult
.那么这有什么问题:
String responseBody = EntityUtils.toString(entity);
System.out.println("finalResult"+responseBody.toString());
Run Code Online (Sandbox Code Playgroud)
???
重要事项这HttpEntity entity = response.getEntity();
等于org.apache.http.conn.BasicManagedEntity@481e8150
.所以问题必须在这里:
String responseBody = EntityUtils.toString(entity);.
请帮忙!!!
waq*_*lam 24
首先,查看您的服务器是否未返回空白响应:
response.getEntity().getContentLength(); //it should not be 0
Run Code Online (Sandbox Code Playgroud)
其次,尝试以下方法将响应转换为字符串:
StringBuilder sb = new StringBuilder();
try {
BufferedReader reader =
new BufferedReader(new InputStreamReader(entity.getContent()), 65728);
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line);
}
}
catch (IOException e) { e.printStackTrace(); }
catch (Exception e) { e.printStackTrace(); }
System.out.println("finalResult " + sb.toString());
Run Code Online (Sandbox Code Playgroud)
小智 8
你可以用这个:
String s = EntityUtils.toString(httpRes.getEntity());
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
61663 次 |
最近记录: |